Can a magnet's magnetic field perform work on another magnet?

AI Thread Summary
The discussion centers on whether a magnet can perform work on another magnet, with participants debating the implications of classical electromagnetism and the Lorentz force. It is established that while a magnetic field does not do work on free charges, it can influence the atomic structure of magnets, indirectly affecting energy transfer. The conversation highlights the complexity of magnetic interactions, noting that classical electromagnetic laws may not fully account for the behavior of permanent magnets under certain conditions. Participants argue about the adequacy of existing theories and the need for rigorous proofs to support their claims. Ultimately, the debate reflects ongoing challenges in reconciling classical electromagnetism with quantum mechanics in understanding magnetic work.
  • #51
You can pick up a paper clip with a magnet. You can pick up another magnet with a magnet. That much is clear. Beyond that, authorities differ.

Respectfully,
Steve
 
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  • #52
Dotini said:
Shocking and disconcerting that physicists and perhaps even textbooks are in disagreement! [..]
As we discovered in the original thread, it's basically a matter of words. :smile: Some people use a (IMHO strange) definition of "work", such that the use of field energy for displacing an object is not "work" done by that field.

I guess that if I pull on an object with a rope and ask if I "did work", some may answer yes, others may answer "no, the rope did the work" and again others may answer that depending on the system boundaries that we regard, if it was me or the rope that did the work. I would say that I performed work on the object by means of the rope.

Miyz said:
I'm lost with all this... Please if someone can simply present an answer.
Yes/No, supporting a simple explanation?
See above; so I simply say Yes, in agreement with Robert Gardner. :-p

My more complete answer (based on the elaborate explanations of others):
Yes, the magnetic field does work by means of induced currents and electric fields.

However it's unclear to me where/how such currents occur in permanent magnets. Does this mean that they heat up? If this was explained somewhere, can someone please provide a link?
 
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  • #53
harrylin said:
See above; so I simply say Yes, in agreement with Robert Gardner.
Good for you Harald - but then you muddy the waters with:
My more complete answer (based on the elaborate explanations of others):
Yes, the magnetic field does work by means of induced currents and electric fields.
What induced currents? [it's true there are c(∇×M) 'induced currents' in the case of that soft iron paper clip, where induced magnetization is significant. Fundamentally though, such 'currents' owing to changing orientation of fundamental spin moments are fictitious entities. In the case of fully magnetized permanent magnets, there is no room to invoke such at all] Have you read through my little piece addressed to vanhees71 in #45? And btw this can be extended not just to permanent magnets but anywhere that magnetic media are involved - e.g. transformers, and real motors incorporating 'soft' iron armatures etc. We are talking about how energy is redistributed in an interacting system, so 'work being done' is as you say perhaps a little ambiguous. What can be said is there is for sure no electrical E.j work being done on those fundamental magnetic entities - electron as magnetic moment. The only consistent classical way of treating them is as perfectly rigid (sans SR length contraction) fictional magnetic dipoles with magnetic charges at each end. That's in terms of their impact on the *externally accessible* system energetics - magnetic susceptibility of the media. There is a somewhat 'delicate' issue raised in my #7 if one follows it through ('excess internal energy'), but it's really a matter for a separate thread that I may later open probably in QM section not here.
 
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  • #54
Q-reeus said:
Good for you Harald - but then you muddy the waters with:
[...]
What induced currents? [..]
Good - so now we are two who are asking that same question! :-p

I did not study your exchange which appears to somewhat challenge "standard science", instead I wait with interest on more explanation by those who make such claims. :smile:
 
  • #55
Then the conclusion of this thread is that magnet's can do work on each other.
But what force exactly is the cause of work?
 
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  • #56
Anyone?!
 
  • #57
You are not going to get a consensus conclusion on this thread. My conclusion is the same as the previous thread since this is still a situation covered by the laws of classical EM. Others have firm differing opinions but no good evidence to support them.

You should form your own opinion either based on evidence and the laws of physics or based on unsubstantiated speculation, as you prefer.
 
  • #58
DaleSpam said:
You are not going to get a consensus conclusion on this thread. My conclusion is the same as the previous thread since this is still a situation covered by the laws of classical EM. Others have firm differing opinions but no good evidence to support them.

You should form your own opinion either based on evidence and the laws of physics or based on unsubstantiated speculation, as you prefer.

So what's your conclusion? What is the basis? I just would like to know.

Claude
 
  • #59
cabraham said:
So what's your conclusion? What is the basis? I just would like to know.

Claude

His first post is the main conclusion. It's the same as the preview thread that I've started, unfortunately Dale and I disagree. I honestly do not believe that the same concept on a "loop" is applied to a "permanent magnet".

Miyz,
 
  • #60
However, we could make this conclusion more debatable. Maybe?
 
  • #61
I can only repeat what has been put already. It is an experimental fact that ferromagnetic and ferrimagnetic media do not respond to an induced magnetic field as though composed of microscopic perfectly conducting classical loop currents. If it were so then net magnetic induction Btot within such media would attempt to be invariant, in keeping with the requirement that no electrical field exist within, or have a tangent component at the surface of, such conducting entities - only satisfied if the net flux enclosed within each such loop current is maintained constant (perfect diamagnetism - see e.g. www.phy.duke.edu/~hx3/physics/Superconductor2.pdf ). And that predicts a net media susceptibility -> - 1. [Magnitude would be somewhat less than unity owing to thermal jostling, and less than 100% achievable volume packing fraction of such loops] Does not happen that way. Actual susceptibilities can run into the hundreds of thousands for magnetically 'soft' media, while essentially zero for permanent magnets in their useful range of use. Quantum mechanics rules here and what is invariant is not enclosed flux within such hypothetical loop currents, but rather the magnitude of the intrinsic electron dipole moment.

To claim E.j work is being done on such intrinsic moments is inviting a severe paradox since, as touched on in #26 "there must somehow be some mysterious energy source which keeps the magnetic dipole moment constant when subjected to external field," (actually, time-changing B field giving rise to non-zero E.j) There is indeed something to this 'mysterious energy source' which bears further thought as per my closing bit in #53. At any rate, actually observed magnetic response, whether of permanent magnets or transformer cores etc., is best thought of in terms of fictitious magnetic dipoles of fixed magnitude - and that property cannot be explained via tiny classically behaving loop currents. And if one cannot then model using such loop currents, the whole argument that all energy exchanges are explained as E.j interactions simply fails.

For real situations there is finite conductivity and it's this generally quite minor induced eddy-current component that can be explained without controversy as E.j interactions. In the case of induced magnetization (e.g. example of soft iron paper-clip attracted to permanent magnet), there is a formal 'induced current' interaction but only in the sense of a varying magnetic moment m in F = (m.B), the interaction being consistently best treated as fundamentally magnetic not electric.
 
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  • #62
DaleSpam said:
You are not going to get a consensus conclusion on this thread. My conclusion is the same as the previous thread since this is still a situation covered by the laws of classical EM. Others have firm differing opinions but no good evidence to support them.

You should form your own opinion either based on evidence and the laws of physics or based on unsubstantiated speculation, as you prefer.

What evidence's do you need? Dale, the basics of all of this is that magnet's certainly can do work. What exactly is doing the work? I find that difficult to prove. However, a known FACT is spread around the field of EM is that magnet certainly can do work. Example: Take them apart and put them back to each other. Now we can debate all night on who is exactly is doing the work but again, magnets can certain do work they have the force,potential to do so. I told you from before that when asked what work is... You would reply that it's the transfer of energy. Ok, fair enough. But for ANY SYSTEM in the universe that transfer's energy there has to be a source of force or multiple force's that would lead to that conclusion eventually. So we need to break it down and find what force/forces that is.


I agreed earlier that magnetic fields/forces do work but INDIRECTLY to a loop of wire. However, in case of a magnet things would totally differ here. When a magnet is placed in a non-uniform magnetic field it certain feel's a force that "force" can do work on that magnet. What generates a non-uniform magnetic field well, that can be another manget or another electromagnet...

Best Regards,
Miyz,
 
  • #63
Ok, the electrical forces are the cause of work. Agreed. However! Who's the main cause of the electrical forces? This is the main question I feel is left ignored and I would say that its the magnetic fields/forces and their interaction that would eventually cause the electrical forces to do work. Without one of those factors. As I said earlier before magnetic fields would generate those electrical force that would eventually cause the work. Without one of them NO WORK would be done on a system.

Electric forces CAN NOT! be generated in this system without the existence of a magnetic field/force. The greater/weaker the field the same goes for the EF. So Mag.F + Elec.F are both proportional to each other.

Does this sound good everyone?(Correct me if I'm wrong/or not liking where this is going)

Miyz,
 
  • #64
Miyz said:
Ok, the electrical forces are the cause of work. Agreed.
Not agreed. You sure seemed to be disagreeing with that position in #62 - what has changed your mind? Apparently my summarized position in #61 has not impressed , or is it a case of not quite getting the main point there?
 
  • #65
Q-reeus said:
Not agreed. You sure seemed to be disagreeing with that position in #62 - what has changed your mind? Apparently my summarized position in #61 has not impressed , or is it a case of not quite getting the main point there?

Im still not sure with my final conclusion. More confused then ever! However, my post #62 makes the most sense to me personally. I find you're post was great! Perfectly well demonstrated but I asked so many all agree that electrical forces are doing the work not magnetic. I don't how to rebuttal to that point honestly because I feel this fact is still not proven properly. However, if you have something please share more.
 
  • #66
Miyz said:
Im still not sure with my final conclusion. More confused then ever! However, my post #62 makes the most sense to me personally. I find you're post was great! Perfectly well demonstrated but I asked so many all agree that electrical forces are doing the work not magnetic. I don't how to rebuttal to that point honestly because I feel this fact is still not proven properly. However, if you have something please share more.
Yes I agree it can get confusing, but it's good to keep in mind the main issue in this thread. We are debating the means whereby *energy* is exchanged/redistributed amongst interacting magnetized structures - say that paper-clip/magnet, or magnet/magnet. These are ferromagnetic (iron & similar compounds) or ferrimagnetic (ferrites) materials whose magnetism is not owing to currents flowing through wires, but chiefly the intrinsic magnetic moment of electrons - with electron orbital contributions significant in ferrites. As covered in say #45 and #61, it is known the electron intrinsic magnetic moment, and to only a slightly lesser degree ferrimagnetic orbital contributions, simply does not 'feel' any electrical forces of the -dA/dt type (result of relative motion or internal reorienting of magnetic material). If it did there would necessarily be a change in the intrinsic magnetic moment as per #61 - and it just does not happen. It's a bit like there being a spinning top on the table. A classical spinning top (the usual ones!) will immediately slow down if one presses down on it with the hands, but an intrinsic quantum top would magically resist all such efforts - as though it just becomes perfectly frictionless. I hope you get the analogy. [STRIKE]Flux[/STRIKE] Spin/magnetic moment quantization forces real magnets to completely ignore electrical fields that would readily induce changed magnitude of magnetic moment in a classical microscopic loop current. [Edit: only wholly true of intrinsic spin magnetic component. Orbital part is more complex and somewhat 'softer' in that orbitals do deform slightly under an applied external B, allowing a small but finite continual response in net magnetic moment. The complete description of all contributions to magnetic response and origins is complex - e.g. "www.appi.keio.ac.jp/Itoh_group/spintech6/lectures/Lec1_Weiss.pdf" Net response very different though to the diamagnetism predicted for E.j action on a classical perfectly conducting loop current]

There continues to be forces felt, but the distribution of such forces and resulting energy redistribution - work done by one part of the system on another, is drastically different between the case of real magnetic materials that reject E.j interactions, and hypothetical media comprised of classical loop currents that would not. The former behave as though rigid dipoles made of magnetic charges, and the 'accessible' energetics in the system is thus rightly attributable to magnetic not electric interactions. As per both #45 and #61, there is a minor additional contribution owing to induced eddy currents in the media. These do conform to electrical E.j type interactions, but are typically tiny wrt the main magnetic energy changes. That's my piece repackaged, and I welcome any constructive critique. Must go. :zzz:
 
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  • #67
These threads can be effective at getting us to think deeply about science & expand our understanding. Unfortunately, there are always people who force fit everything into their preconceived narrow view of the world, & think the world should adopt their viewpoint because it is "right". They use words like "fundamental", "such and such can NEVER do work", etc.

I am now convinced that there are those who refuse to accept that B forces can do work despite evidence to the contrary. They spin everything & change rules at will just to suit their foregone conclusion. The final answer is simply that under dynamic conditions E & B always coexist mutually. You can never have one w/o the other.

Energy is transferred in & out of both of these fields. Both are doing energy transfer, but depending on the conditions, one of them may be what provides force & hence that quantity is doing work. But the other is supplying energy & without that other field/force, it would not be able to do work alone because they are mutually inclusive.

So when we say that E does work, or that B does work, it's too easy to say "no, it's the other one doing the work" because conservation of energy is immutable. Without the other, well, just forget it.

So can B do work lifting a magnet or paper clip? The naysayers have provided equations & arguments saying no, but I find an inconsistency in their position worth highlighting.

Lorentz force is agreed upon as being all important. It has 2 components, Fe due to electric force, & Fm due to magnetic force. We know Fe = q*E, & Fm = q*(uXB). So why is it that E can do work, yet B cannot do work? The classical naysayer answer is that E can act in the direction of motion, but cannot. B acts normal to motion & thus cannot do work, since B only can change a charged particle's momentum, but not its KE.

Personally, I agree with that. If a force acts in a manner on an entity such that it is not aligned with the entity's motion/path, then that force cannot be what is doing work. This is why an electron moving through a B field & an E field incurs a change in KE due solely to E, not to B. Its momentum change is due to both, but its KE change is due entirely to E. So far I really doubt that anyone would dispute me.

But when a magnet lifts another magnet, which force is doing the work, B or E? In the motor thread I provided sketches, but this is the magnet thread. So I ask this, which field, B or E, is along the direction of the moving magnet as it ascends? That field is doing the work. In the motor thread, the B force was along the rotor motion so it had to be doing the work. Can somebody provide a sketch of the magnetic forces & their orientation? My sketches do not seem to convince them. Without drawing the forces out, I cannot be sure, but it sure looks like B forces do the work lifting the magnet. Again, if that is not the case, I just ask that you sketch the vectors showing how the E force acts in the vertical direction. Thanks in advance.

Claude
 
  • #68
Miyz said:
His first post is the main conclusion. It's the same as the preview thread that I've started, unfortunately Dale and I disagree. I honestly do not believe that the same concept on a "loop" is applied to a "permanent magnet".
Can you cite any peer reviewed evidence showing that Maxwells equations do not apply to a permanent magnet? If not, then on what do you base your belief?
 
  • #69
Q-reeus said:
To claim E.j work is being done on such intrinsic moments is inviting a severe paradox since, as touched on in #26 "there must somehow be some mysterious energy source which keeps the magnetic dipole moment constant when subjected to external field," (actually, time-changing B field giving rise to non-zero E.j)
And your evidence for this is ...?
 
  • #70
Miyz said:
What evidence's do you need? Dale, the basics of all of this is that magnet's certainly can do work. What exactly is doing the work? I find that difficult to prove.
Then you should look at the proof I provided. It is not that difficult, and once you understand it you see that it applies to all of classical EM.


Miyz said:
Iagreed earlier that magnetic fields/forces do work but INDIRECTLY to a loop of wire. However, in case of a magnet things would totally differ here.
How so? Which of Maxwells equations are violated for a magnet?
 
  • #71
Miyz said:
Ok, the electrical forces are the cause of work. Agreed. However! Who's the main cause of the electrical forces? This is the main question I feel is left ignored and I would say that its the magnetic fields/forces and their interaction that would eventually cause the electrical forces to do work. Without one of those factors. As I said earlier before magnetic fields would generate those electrical force that would eventually cause the work. Without one of them NO WORK would be done on a system.

Electric forces CAN NOT! be generated in this system without the existence of a magnetic field/force. The greater/weaker the field the same goes for the EF. So Mag.F + Elec.F are both proportional to each other.

Does this sound good everyone?(Correct me if I'm wrong/or not liking where this is going)

Miyz,
Sounds good to me, although I don't know about them being proportional.
 
  • #72
DaleSpam said:
And your evidence for this is ...?
Just follow the logic. I will turn this around and ask you to explain how it could be otherwise - how do *you* explain the known magnetic behavior of real magnetic materials with the notion that E.j type work is even possible on such (sans eddy currents as I have explained). And btw, still waiting for your answers (that's plural) to #49. Ready to do that now? I slipped back to edit #66, so not hanging around.
 
  • #73
cabraham said:
The final answer is simply that under dynamic conditions E & B always coexist mutually. You can never have one w/o the other.
Agreed. And under the right conditions B can be the dominant source of both E and j. But the work done is always equal to E.j.

cabraham said:
I am now convinced that there are those who refuse to accept that B forces can do work despite evidence to the contrary.
What evidence? Do you have any good evidence that you can cite that says the work done is not equal to E.j?
 
  • #74
Q-reeus said:
I will turn this around
Yes, that is your usual approach: in the absence of good evidence supporting your claim try to hide the fact behind demands that I provide disproof of your speculative claim.

I have provided my claim with good evidence. You have provided your contrary claim, but without good evidence. So your claims are just speculation, and I have no intention to be lured in.
 
  • #75
DaleSpam said:
Agreed. And under the right conditions B can be the dominant source of both E and j. But the work done is always equal to E.j.

What evidence? Do you have any good evidence that you can cite that says the work done is not equal to E.j?

1st bold - of course the work done is equal to E.J. Who says otherwise? I certainly do not.

2nd bold - I've always stated that the work done IS equal to E.J. Dale, if I say something that is wrong then tell me. Please don't put words in my mouth. Here it is straight from Claude:

Just because the work done equals E.J does not mean that E or J is actually doing the work. Without E.J, the B field cannot energize & cannot do work. B does the work because the Lorentz force associated with B, i.e. the mag component of Lorentz force, acts along the direction of motion, whereas E & J do not.

But w/o E.J, there is no B field energy. I agree that the work done can be computed per E.J, but that energy is transferred to a B field, then motion is implemented, so that the motion resulting in KE results in a reduction in B field energy. Energy is always conserved.

Seeing that we agree in the fact that work done originates from E.J, we need not argue that point. We agree on E.J being the value of work done producing motion plus any incurred energy storage and/or loss.

My point is that those who claim B does no work, support their position by citing that with free charges B acts in the wrong direction to do work. There is no component of Lorentz mag force acting along an e- motion. It is normal to the motion meaning that B does no work on the e-. I accept that. But the E field which imparts energy to the e- may be induced by a time varying magnetic field. A B field imparts energy to the E field, then the E force does work on the e-.

E did the work, but B provides energy for the E field. Which one did the work is determined by the direction of the fields with regard to the motion. But neither does it alone. B has energy but cannot impart energy to the e-. E can impart energy to the e-, but cannot have said energy w/o B.

It seems we also agree on the principle that E & B are mutually inclusive under dynamic conditions. We agree that E.J is the value of energy transferred to the magnet plus storage & loss quantities. The only sticking point still under scrutiny is the definition of which field is really "doing work". I believe that is determined by the direction of the force vectors.

Sometimes it's E, other times it's B. But neither can do it alone. BR.

Claude
 
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  • #76
DaleSpam said:
Q-reeus: "I will turn this around"
Yes, that is your usual approach: in the absence of good evidence supporting your claim try to hide the fact behind demands that I provide disproof of your speculative claim.
This borders on defamatory.
I have provided my claim with good evidence. You have provided your contrary claim, but without good evidence. So your claims are just speculation, and I have no intention to be lured in.
BS! I'm calling your bluff on this one. For starters - face up, at long last, to actually answering those questions I posed of you in #49 - or in your strange world is that considered to being 'lured in'? When you finally admit your wildly speculative and unsupported assertion there re 'Planck scale' for one is a load of crap, you may gain at least some vestige of moral credibility for admitting to error. Further on from that, I call upon you to actually provide some substantive and logically coherent, point-by-point rebuttal to either my #61 or #66. It is not I who hides behind rhetoric on this! Fact is, all your 'good evidence' is completely misplaced and wrongly applied when it comes to considering *quantum mechanically* governed intrinsic magnetic moments. No? Well then do as I have requested and we shall see how far you get!
 
  • #77
cabraham said:
1st bold - of course the work done is equal to E.J. Who says otherwise? I certainly do not.

2nd bold - I've always stated that the work done IS equal to E.J.
Then I think that we do not have a substantive disagreement. We will make all of the same experimental predictions in all cases. I am somewhat disinclined to argument about interpretational issues when the facts are agreed upon.

cabraham said:
I agree that the work done can be computed per E.J, but that energy is transferred to a B field, then motion is implemented, so that the motion resulting in KE results in a reduction in B field energy.
I don't think that this is correct. In fact, I think that this is exactly backwards in the case of one permanent magnet doing work on another. While both magnets are stationary, there is no E field and therefore no work is done. Once one of the magnets starts moving the moving B field causes an E field and work is done. If anything the B field transfers energy to the E field and then to work. I.e. the work done by decreasing B is indirect, via its influence on E and j, as I said on the first page.

I am not sure if you agree with the facts here also and just not the interpretation or what?
 
  • #78
DaleSpam said:
Then I think that we do not have a substantive disagreement. We will make all of the same experimental predictions in all cases. I am somewhat disinclined to argument about interpretational issues when the facts are agreed upon.

I don't think that this is correct. In fact, I think that this is exactly backwards in the case of one permanent magnet doing work on another. While both magnets are stationary, there is no E field and therefore no work is done. Once one of the magnets starts moving the moving B field causes an E field and work is done. If anything the B field transfers energy to the E field and then to work. I.e. the work done by decreasing B is indirect, via its influence on E and j, as I said on the first page.

I am not sure if you agree with the facts here also and just not the interpretation or what?

I know a moving magnet has an E field with it. But in what direction are E & B acting. Dale you cannot see your own prejudice. Instead of sketching the orientation of the force vectors, you simply re-iterate the already universally known truth that B cannot exist w/o E in dynamic conditions. I've already said yes to this.

Rather than try to understand the direction of the forces & the path of integration regarding the work done, you instead focus on the fact that B cannot do anything w/o E, but we already know that. So how about drawing us a picture showing the direction of E, B, & the motion of the magnet being lifted. Of course a moving magnet has an E field. But that E force cannot be what is lifting the magnet. Let's examine the chronology of events.

The lower magnet is at rest, the upper magnet is an electromagnet which turns on at time = 0. The lower magnet is at rest & has no E field, just B. The force between the 2 magnets lifts upward on the lower magnet. Just before the lower magnet ascended, it felt an upward force. But this force has to be due to B, not E. E is still zero as the magnet is not yet moving.

Once the magnet begins its ascent it generates an E field. But said E force cannot be what lifts the magnet in the 1st place. Since Lorentz force due to B is directed upward, & the motion is upward, it is clear that the B field is providing the Lorentz force which lifts the magnet.

I can't understand why this issue can be controversial at all! It works out when you keep track of the vector directions. Again, for the I forget how many times, if you feel otherwise, then:

DRAW A PICTURE!

Thanks & BR.

Claude
 
  • #79
cabraham said:
I know a moving magnet has an E field with it. But in what direction are E & B acting. Dale you cannot see your own prejudice. Instead of sketching the orientation of the force vectors, you simply re-iterate the already universally known truth that B cannot exist w/o E in dynamic conditions. I've already said yes to this.

Rather than try to understand the direction of the forces & the path of integration regarding the work done, you instead focus on the fact that B cannot do anything w/o E, but we already know that. So how about drawing us a picture showing the direction of E, B, & the motion of the magnet being lifted. Of course a moving magnet has an E field. But that E force cannot be what is lifting the magnet. Let's examine the chronology of events.

The lower magnet is at rest, the upper magnet is an electromagnet which turns on at time = 0. The lower magnet is at rest & has no E field, just B. The force between the 2 magnets lifts upward on the lower magnet. Just before the lower magnet ascended, it felt an upward force. But this force has to be due to B, not E. E is still zero as the magnet is not yet moving.

Once the magnet begins its ascent it generates an E field. But said E force cannot be what lifts the magnet in the 1st place. Since Lorentz force due to B is directed upward, & the motion is upward, it is clear that the B field is providing the Lorentz force which lifts the magnet.

I can't understand why this issue can be controversial at all! It works out when you keep track of the vector directions. Again, for the I forget how many times, if you feel otherwise, then:

DRAW A PICTURE!

Thanks & BR.

Claude

I think the statement that Maxwell’s equations don’t apply to the carriers in a permanent magnet is misleading. There are magnetic domains that can be defined by rigid boundaries. The electric currents don’t have to be thought of as looping around atoms. One can easily envision the electric currents as looping around on the boundary of the magnetic domains. On the length scale of the magnetic domains, the electric charge carriers and their matrix behave as classical particles. No quantum mechanics is needed.
The dynamics on an atomic scale can be ignored. The description of what happens is completely self consistent on the length scale of the magnetic domains. A magnetic domain can be considered a container of superfluid charge carrier confined by a boundary held together by rigid forces. The only forces act normal to the surface of the boundary of the charge carriers. It is these forces that do work on the charge carriers.
On the length scale of a magnetic domain, the magnetic field is not doing work on the carrier. The magnetic field applies a torque to the electric current loop that rotates the loop on the surface of the magnetic domain. The rigid body forces on the surface of the magnetic domain are doing work on the electric charge carriers. However, the rigid body forces are not part of the magnetic field.
The rigid body forces on the surface of a domain are no more “quantum mechanical” than the rigid body forces in any other solid. On an atomic level, it may be necessary to take into account the wave nature of the carriers. On the domain level, the forces can be described by phenomenological parameters.
Maxwell’s equations are usually used with constitutive relations, anyway. These constitutive relations are basically classical models that are valid on a large length scale, but which take into account the quantum mechanics on an atomic scale. Ohms law is an example of a constitutive relation. London’s Law for superconductors is also a constitutive relation.
I am not going to draw pictures. A magnetic domain can have a highly irregular shape. However, I will include some links to articles. You can see by their equations that Maxwell's equations are still being used.
Here are some links showing how the dynamics of a magnetic domain can be modeled by an effective eddy current and semiclassical physics.
http://pil.phys.uniroma1.it/~fran/jdv13i1pL15.pdf
“The contribution made by eddy currents to the effective mass
of a magnetic domain wall
JEL Bishop
Abstract. The eddy current drag on a moving domain wall is proportional, not to the
instantaneous wall velocity, but to a moving average of its recent velocities. Thus an
oscillating domain wall experiences an eddy force component in quadrature with its
velocity that may formally be attributed to a negative effective ‘eddy mass’. The frequency dependences of the eddy mass and eddy damping constant are calculated for
some simple model domain walls.”

http://ci.nii.ac.jp/naid/110004637004
“In ferromagnetic substance, the origin of internal friction under low stress amplitude has been considered to be due to two kinds of eddy currents, the first named macroscopic eddy current was studied by Brown and its theoretically predicted contribution to internal friction was known to be consistent with the experimental data. But the second named microscopic eddy current has not yet been investigated except in demagnetized state. In this paper, the latter was calculated theoretically as a function of the magnetization and the results were compared with the experimental data obtained with the substances which have neglisibly small anisotropic energy.”
http://arxiv.org/pdf/0706.2122.pdf
“In conducting ferromagnetic materials, a moving domain wall induces eddy currents in the sample which give rise to an effective retarding pressure on the domain wall. We show here that the pressure is not just proportional to the instantaneous velocity of the wall, as often assumed in domain wall models, but depends on the history of the motion.”
“Once the solution of Maxwell equation with the appropriate boundary condition is given, the average eddy current pressure on the wall is obtained by integrating the magnetic field over y at the wall position x = 0:”
 
  • #80
Q-reeus said:
BS! I'm calling your bluff on this one. For starters - face up, at long last, to actually answering those questions I posed of you in #49 - or in your strange world is that considered to being 'lured in'?
Yes, that is what I call being lured in.

Before we worry about one of the tangents way down in post 49 you need to provide good evidence supporting your original thesis from back in post 5:
Q-reeus said:
In short, permanent magnets do not obey classical EM in this important respect, and it cannot be maintained that dW = E.j dv covers the situation.
If you cannot do that then all of the subsequent discussion is an irrelevant distraction.
 
  • #81
cabraham said:
Instead of sketching the orientation of the force vectors, you simply re-iterate the already universally known truth that B cannot exist w/o E in dynamic conditions. ...

DRAW A PICTURE!
The thing is that I don't think that drawing a picture is useful in general. You can draw a picture, and it can help you for one scenario. But a general derivation works for all scenarios. That is why we do general derivations in the first place, to learn general principles that work for all cases regardless of the details.

I think your reliance on pictures is leading you astray. Furthermore, the pictures you draw show forces, which are not the same as work. The work is E.j, always, as you also recognize, but interpret differently.

Btw, if I were to draw a picture I would not do a permanent magnet and an electromagnet. I would stick with the OP's scenario of two permanent magnets. There you do not have an E field "energizing" a B field, as you like to say. It is the other way around.
 
  • #82
DaleSpam said:
Q-reeus: ..For starters - face up, at long last, to actually answering those questions I posed of you in #49 - or in your strange world is that considered to being 'lured in'?
Yes, that is what I call being lured in.
Then I pity you as someone whose ego evidently prevails over humility and honesty.
Before we worry about one of the tangents way down in post 49 you need to provide good evidence supporting your original thesis from back in post 5:
Q-reeus: "In short, permanent magnets do not obey classical EM in this important respect, and it cannot be maintained that dW = E.j dv covers the situation."
If you cannot do that then all of the subsequent discussion is an irrelevant distraction.
Oh my - bet you did a lot of trawling before finding the one statement that makes me 'vulnerable'. I'll be honest and admit that the one part of the above quote: "permanent magnets do not obey classical EM in this important respect," was wrongly stated per se. I should have said and meant it to mean "...permanent magnets do not respond classically to Faraday's law..." And everything since should have left no doubt that was the real intent there. So with that awful admission cleared up - how about you fulfill your side of it and do what was asked in #76. Don't keep telling me I'm wrong unless you can detail just how my argument fails. It's all there - pick either #61 or #66 (probably a little better) and explain to all and sundry just exactly where it goes wrong. Is that not within your capability? Notice I said explain - and that means a reasoned, detailed argument. Go for it!
 
  • #83
Darwin123 - your lengthy piece in #79 is addressed to cabraham but it's thrust seems aimed chiefly at myself. None of your referenced quotes affects my argument. They deal with equivalent representations of how applied *magnetic* fields induce changed magnetization via domain wall motions. Chalk and cheese situation. Intrinsic spin/magnetic moment simply cannot be modeled *in respect of it's response to an applied time-changing B -> solenoidal E field* as though a classical circulating current - whether arbitrarily applied to single domains or whatever other scale one chooses. In #5 I emphasized the so-called surface currents of a magnetized body as the natural scale/boundary to choose, but that's irrelevant to what really matters here. I extend the same invitation to you as to DaleSpam - if E.j work is being done on those domains, or whatever other grouping of intrinsic moments one cares to choose, explain why the response is not weak diamagnetism! It's all set out in #61, #66.
 
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  • #84
Ow my ow my this thread just became a mess of words.
 
  • #85
Dale, Claude, Q-reeus.

YOU'RE ARGUING on something that should have a basic answer.
I've contacted (Mod note: Name deleted) to help me out.

Now here is the e-mail:"On 8/22/12 7:24 AM, miyze adam wrote:
Thank you professor from you're example's I've concluded that magnetic field/force can do no work on a free charge or a loop of wire.
However, in case of a permanent magnet's magnetic field/force applied on another magnet. Is there work being done?

>>>YES
In general can magnet's do work on each other?

>>>Well, if work is being done, it is NOT the magnetic field that does it. However, a moving magnet generates also an ELECTRIC field, and the electric field can do work.
Thank you Professor.

Regards,

Miyze.
"

That was his reply to my previous e-mail. My question are in black and his answers are in red.
I wanted to post this ASAP. However, got busy with collage... Anyways you all have to understand that the MAIN FORCE! that does work is certainly the electrical force. I agree with that point but what GENERATES THAT ELECTRICAL FORCES? the magnetic field! Now are the magnetic field doing work? CERTAINLY.

Now as I've agreed with Claude previously is that without the Mag.fields the electrical forces can't do work WHY? because they are not created by the magnetic field. Simple.

Now Dale they are all proportional to each other! The greater the magnetic field the higher the electrical forces so yea their proprtional to each. Mf = Ef, Its as if I'm a student and the more homework the proferssor assagin's the more work IM DOING( Student = electric force/field, Prof = Magnetic force/field.) Simple as that. So yea I think I've found out the simplest answer to this thread that we can all agree upon? Yes! Magnetic field/force can do work to create the electrical field thatould evnetually do work on the other MANGET.
Miyz,
 
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  • #86
Miyz said:
Dale, Claude, Q-reeus.

YOU'RE ARGUING on something that should have a basic answer.
I've contacted (Mod note: Name deleted) to help me out.

Now here is the e-mail:

"On 8/22/12 7:24 AM, miyze adam wrote:

Thank you professor from you're example's I've concluded that magnetic field/force can do no work on a free charge or a loop of wire.
However, in case of a permanent magnet's magnetic field/force applied on another magnet. Is there work being done?

>>>YES

In general can magnet's do work on each other?

>>>Well, if work is being done, it is NOT the magnetic field that does it. However, a moving magnet generates also an ELECTRIC field, and the electric field can do work.
[..]

Magnetic field/force can do work to create the electrical field thatould evnetually do work on the other MANGET.

Yes, that's how I also understood it (see my post #52). Note that his opinion is just one of the opinions in this thread. Remains the question of how this electric field comes about in a permanent magnet. And much disagreement seems also to be about that. Are these due to currents that heat the magnets (eddy currents)?
 
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  • #87
Miyz said:
However, in case of a permanent magnet's magnetic field/force applied on another magnet. Is there work being done?
>>>YES
In general can magnet's do work on each other?
>>>Well, if work is being done, it is NOT the magnetic field that does it. However, a moving magnet generates also an ELECTRIC field, and the electric field can do work.
All seems to in black and..red. Sorry but there needs to be some context applied there. What was Prof. Griffith's definition of 'work being done' exactly? Could be he meant just conversion of mechanical to heat via eddy current generation, in which case I would agree. Maybe email again Miyz, and get specifics on just what he meant exactly by 'work being done'. I may be in a minority of one here but stick to the position no electrical work is done on the chief source of permanent magnetism - electron intrinsic magnetic moments. Period. Considering asking him specifically if and how electrical work can be done on an intrinsic electron magnetic moment. That would be interesting. Then again maybe I should just go and ring-in Lubos Motl here! Whatever. I can agree there is 'virtual work' being done by pretending an intrinsic moment responds diamagnetically to a -dA/dt E field, but it does not so respond. So where next. What's on TV right now?
 
  • #88
Q-reeus said:
Oh my - bet you did a lot of trawling before finding the one statement that makes me 'vulnerable'.
Hardly. That is the exact quote that I objected to in post 6 and have been requesting some evidence to support ever since.

Q-reeus said:
I'll be honest and admit that the one part of the above quote: "permanent magnets do not obey classical EM in this important respect," was wrongly stated per se.
Since you now agree that permanent magnets obey Maxwell's equations then you must agree that the work done on a permanent magnet is necessarily given by E.j. (It is possible to take a stance like cabraham's where you agree that the work is equal to the quantity E.j but say that it work is not "done by" E. But in any case the amount of work done must be equal to E.j)

Q-reeus said:
I should have said and meant it to mean "...permanent magnets do not respond classically to Faraday's law..." And everything since should have left no doubt that was the real intent there.
Just for clarification. By "respond classically" I believe that you mean something like "respond as though composed of a loop of current in a zero-resistance, zero-susceptibility conductor"? If not, can you clarify what you intend by "respond classically"?

If that is what you mean then I agree with the statement, although I wouldn't use the phrase "respond classically" to describe that model.

Q-reeus said:
It's all there - pick either #61 or #66 (probably a little better) and explain to all and sundry just exactly where it goes wrong. Is that not within your capability? Notice I said explain - and that means a reasoned, detailed argument. Go for it!
OK.
It is an experimental fact that ferromagnetic and ferrimagnetic media do not respond to an induced magnetic field as though composed of microscopic perfectly conducting classical loop currents.
I agree. Ferromagnetic media do not respond to an induced magnetic field as though composed of microscopic perfectly conducting classical loop currents, particularly not if you mean in a zero-resistance zero-susceptibility material.

This is not, in fact, how ferromagnetic media are modeled in classical EM. What must be supplied in classical EM is a constituitive relationship between M and either H or B. For example, see here. For a ferromagnetic material over a reasonably small range of H (where hysteresis does not occur) you could approximate the constituitive relationship as something like M(H)=M_0+k H. The constituitive relationships cannot be derived under classical EM, and are simply determined empirically (or calculated from other theories like QM) and are used as conditions on the fields. However, once you have the constituitive relationships describing the matter, then classical EM applies and Maxwell's "macroscopic" equations may be used to accurately describe the interaction, including that of two permanent magnets.

This is discussed in depth in Jackson's "Classical Electrodynamics" starting on pages 13-16 and continued in chapter 6.
 
  • #89
Miyz said:
YOU'RE ARGUING on something that should have a basic answer.
It has an answer ("basic" is hard to define). But whether or not something has an answer does not mean that people will agree on it. I think you are expecting too much by assuming 1) that if an answer is correct then everyone will agree on it and 2) that the correct answer corresponds to your preconceptions.

Btw, it sounds like your professor agrees with my position. My own opinion, as always, is open to revision based on further evidence and information, but as of today none of the arguments presented by Q-reeus or cabraham seem to carry the weight of evidence of Maxwell's equations.

However, cabraham at least recognizes the validity of Maxwell's equations and agrees on the amount of work being done and simply interprets the equations differently, so I find his position the most palatable of the contrary ones.

Miyz said:
Now Dale they are all proportional to each other! The greater the magnetic field the higher the electrical forces so yea their proprtional to each.
The property you are describing here is linearity. Maxwell's equations are indeed linear. That isn't the same as proportional.
 
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  • #90
DaleSpam said:
It has an answer ("basic" is hard to define). But whether or not something has an answer does not mean that people will agree on it. I think you are expecting too much by assuming 1) that if an answer is correct then everyone will agree on it and 2) that the correct answer corresponds to your preconceptions.

Btw, it sounds like your professor agrees with my position. My own opinion, as always, is open to revision based on further evidence and information, but as of today none of the arguments presented by Q-reeus or cabraham seem to carry the weight of evidence of Maxwell's equations.

However, cabraham at least recognizes the validity of Maxwell's equations and agrees on the amount of work being done and simply interprets the equations differently, so I find his position the most palatable of the contrary ones.

The property you are describing here is linearity. Maxwell's equations are indeed linear. That isn't the same as proportional.
Prof.David said its the moving magnetic field that generates the electric field. Now where in Maxwell's equations exactly that states that their not proportional?

Dale, do you agree with my final point? However, you could agree that magnetic field/force's value = the electrical field/force generated.

That simply means M = E so if one value is 100 the other would be the same. I'm not sure what you mean by linearity, and hope you get my point. That we can finally AGREE upon.
 
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  • #91
Does my post (#85) makes sense and do you agree?

Yes/No, with a simple explanation why...
Miyz,
 
  • #92
Miyz said:
Prof.David said its the moving magnetic field that generates the electric field. Now where in Maxwell's equations exactly that states that their not proportional?
The professor is referring to Faraday's law which states:
\nabla \times \mathbf E = -\frac{\partial \mathbf B}{\partial t}

When you say they are proportional then you are saying:
\mathbf E = k \mathbf B

Which is not at all equivalent to Faraday's law.

What I was saying about linearity is that if you have E and B such that they satisfy Maxwell's equations (E and B are not proportional) then if you double E then you will also double B and get a valid solution to Maxwell's equations. This is part of what it means for system of differential equations to be linear.
 
  • #93
DaleSpam said:
The professor is referring to Faraday's law which states:
\nabla \times \mathbf E = -\frac{\partial \mathbf B}{\partial t}

When you say they are proportional then you are saying:
\mathbf E = k \mathbf B

Which is not at all equivalent to Faraday's law.

What I was saying about linearity is that if you have E and B such that they satisfy Maxwell's equations (E and B are not proportional) then if you double E then you will also double B and get a valid solution to Maxwell's equations. This is part of what it means for system of differential equations to be linear.


Or vice versa, if you double B , E will also double based on the equation. Right Dale?
 
  • #94
DaleSpam said:
Q-reeus: "I'll be honest and admit that the one part of the above quote: "permanent magnets do not obey classical EM in this important respect," was wrongly stated per se".
Since you now agree that permanent magnets obey Maxwell's equations then you must agree that the work done on a permanent magnet is necessarily given by E.j. (It is possible to take a stance like cabraham's where you agree that the work is equal to the quantity E.j but say that it work is not "done by" E. But in any case the amount of work done must be equal to E.j)
You misconstrue my position re ME's - I clarified in the part you excerpted from above, then include below, but fail to put it together. You continue to fall back though in #89 to outright misrepresentation: "However, cabraham at least recognizes the validity of Maxwell's equations" - implying in the context that I do not. I call upon you to withdraw those remarks as outright false.
Q-reeus: "I should have said and meant it to mean "...permanent magnets do not respond classically to Faraday's law..." And everything since should have left no doubt that was the real intent there."
Just for clarification. By "respond classically" I believe that you mean something like "respond as though composed of a loop of current in a zero-resistance, zero-susceptibility conductor"? If not, can you clarify what you intend by "respond classically"?
Huh!? An obvious yes to that, given it has been stated quite clearly many times from #5 onwards - no sudden change now. More later.
I agree. Ferromagnetic media do not respond to an induced magnetic field as though composed of microscopic perfectly conducting classical loop currents, particularly not if you mean in a zero-resistance zero-susceptibility material.
Oh? Then given your stand you are in deep trouble without realizing it.
This is not, in fact, how ferromagnetic media are modeled in classical EM. What must be supplied in classical EM is a constituitive relationship between M and either H or B. For example, see here.
A strange reference, would have expected something more comprehensive and to the point, like that given back in #66.
For a ferromagnetic material over a reasonably small range of H (where hysteresis does not occur) you could approximate the constituitive relationship as something like M(H)=M0+kH. The constituitive relationships cannot be derived under classical EM, and are simply determined empirically (or calculated from other theories like QM) and are used as conditions on the fields. However, once you have the constituitive relationships describing the matter, then classical EM applies and Maxwell's "macroscopic" equations may be used to accurately describe the interaction, including that of two permanent magnets.
And the constiutive relationship B = μ0H(1+χ) when applied to magnetic media makes it very clear such media cannot be treated as tiny classical current loops - so we come full circle on that one.
This is discussed in depth in Jackson's "Classical Electrodynamics" starting on pages 13-16 and continued in chapter 6.

That and similar treatments afaik never ask or answer the question of just how or where the E.j 'electrical work' done on an intrinsic moment appears. I have asked you often enough now and you continue to duck it - if as you maintain E.j work is literally done on a magnet, which is a collection of intrinsic moments, explain why those moment magnitudes are totally unaltered. Can you? When two fully and uniformly magnetized bar magnets, pointed end-to-end, are allowed to draw together, explain in your own words why there is zero change in the fictitious Amperian circulating currents in both magnets. Sure, and this is something I have never denied, there is a formal quantity amounting to integrating E = -dA/dt over time on those surface Amperian currents that numerically gives the work done in the attraction process. And nothing of substance changes in this matter when more realistic changes in material magnetization are considered - one is still dealing overwhelmingly with intrinsic moments - whether or not they may reorient in response to forces and torques owing to external *magnetic* fields.

But as I have always maintained, there is no actual *electrical* E.j type work done on those fictitious 'currents' for the simple reason they do not respond by changing. Such seemingly magical behavior cannot be classically accounted for - there are no tiny feedback circuitry & batteries maintaining I = constant against the E in E.j The magnetic response is that of a system of microscopic fictitious, perfectly rigid 'true magnetic dipoles'. Hence the formal E.j quantity is rightly attributable to magnetic energy change - the character of which one might ultimately owe to somewhat mysterious 'work done' by QM 'forces' maintaining intrinsic spin constant. Or just accept quantization of the intrinsic moment, if thought of as a tiny loop current, switches-off any response to a solenoidal E field. Recalling an electron is both a quantized charge and a quantized magnetic moment, it is quite free to respond to any applied E *as a point charge*, hence eddy-currents. I'm about done arguing this - too much energy wasted fighting misrepresentation, evasiveness, and continually cycling worn out arguments. Must go.
 
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  • #95
Q-reeus said:
You misconstrue my position re ME's - I clarified in the part you excerpted from above, then include below, but fail to put it together. You continue to fall back though in #89 to outright misrepresentation: "However, cabraham at least recognizes the validity of Maxwell's equations" - implying in the context that I do not. I call upon you to withdraw those remarks as outright false.
If you accept Maxwells equations then you must accept that the work done on matter is E.j. The former implies the latter.
 
  • #96
The more I know, the less I understand...

Professor Krab said:
You need not change any magnetic field. If big magnets are confusing you, think of 2 elementary particles with no charge, but with magnetic moment. There are magnetic forces between them. These forces are not perpendicular to velocities and so they do work.
[ref]

Professor Moore said:
The magnetic field does NO work on a charged particle. In fact, the only thing a magnet can do work on is another magnet or a ferromagnetic material.
[ref]

Gokul43201 said:
\mathbf{F} = \mu \left( \frac{\partial \mathbf{B}}{\partial z} \right)
It is this last force that attracts magnets to each other, or iron filings to a magnet.
[ref]

I have spent the last 16 hours trying to figure this out on my own, but my math is in dreadful disrepair. I spent about two hours going through my Halliday and Resnick(1986), and could find no reference to magnet - magnet interactions, except for a single equation:

F=(3μ0/2∏)μ2/r2

I could not find anything in their description of Maxwell's equations that implies that a pair of magnets cannot do work on each other.

time varying E field: n/a
time varying B field: n/a
E field on a gaussian surface: n/a
B field is zero: n/a

And the Lorentz force law seems to be completely non-applicable also.

Standard disclaimer: Everything I claim to know on this subject, I learned today. And being somewhat senile, will forget by morning.
 
  • #97
OmCheeto said:
The more I know, the less I understand...

[ref]

[ref]

[ref]

I have spent the last 16 hours trying to figure this out on my own, but my math is in dreadful disrepair. I spent about two hours going through my Halliday and Resnick(1986), and could find no reference to magnet - magnet interactions, except for a single equation:

F=(3μ0/2∏)μ2/r2

I could not find anything in their description of Maxwell's equations that implies that a pair of magnets cannot do work on each other.

time varying E field: n/a
time varying B field: n/a
E field on a gaussian surface: n/a
B field is zero: n/a

And the Lorentz force law seems to be completely non-applicable also.

Standard disclaimer: Everything I claim to know on this subject, I learned today. And being somewhat senile, will forget by morning.


Reasonable & Interesting point.
 
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  • #98
OmCheeto said:
And the Lorentz force law seems to be completely non-applicable also.
Maxwells equations describe the fields interactions with themselves. The Lorentz force law describes the interaction between the fields and matter. You cannot have any work done (or any other influence) on matter without the Lorentz force law.
 
  • #99
DaleSpam said:
Maxwells equations describe the fields interactions with themselves. The Lorentz force law describes the interaction between the fields and matter. You cannot have any work done (or any other influence) on matter without the Lorentz force law.

:cry:

Sounds like I have 16 more hours of studying the Lorentz force in front of me, as the wiki quick synopsis doesn't seem to indicate this:

Variations on this basic formula describe the magnetic force on a current-carrying wire (sometimes called Laplace force),
We're talking about two permanent magnets. No wire involved.

the electromotive force in a wire loop moving through a magnetic field (an aspect of Faraday's law of induction),
We're talking about two permanent magnets. No wire loop or movement involved.

and the force on a particle which might be traveling near the speed of light (relativistic form of the Lorentz force).
This might be relevant, as my 16 hours of study indicated that magnetic dipole moments might be relativistically based.
Please don't ask for a reference. I stopped at scores of web sites yesterday.
But laymen like myself are always trying to put 2 + 2 together, even though we have forgotten our math.

For the neutron, this suggests that there is internal structure involving the movement of charged particles, even though the net charge of the neutron is zero. If g=2 were an expected value for the proton and g=0 were expected for the neutron, then it was noted by early researchers that the the proton g-factor is 3.6 units above its expected value and the neutron value is 3.8 units below its expected value. This approximate symmetry was used in trial models of the magnetic moment, and in retrospect is taken as an indication of the internal structure of quarks in the standard model of the proton and neutron.
[ref]

Well, something's going on that's creating a dipole magnet. Must be whirling charges of some kind. :rolleyes:

(15 minutes of Lorentz Force wiki study)

wiki said:
In real materials the Lorentz force is inadequate to describe the behavior of charged particles, both in principle and as a matter of computation. The charged particles in a material medium both respond to the E and B fields and generate these fields. Complex transport equations must be solved to determine the time and spatial response of charges, for example, the Boltzmann equation or the Fokker–Planck equation or the Navier–Stokes equations. For example, see magnetohydrodynamics, fluid dynamics, electrohydrodynamics, superconductivity, stellar evolution. An entire physical apparatus for dealing with these matters has developed. See for example, Green–Kubo relations and Green's function (many-body theory).
[ref]

This is going to take longer than 16 hours.

hmmm...

OmCheeto said:
I'm a former electrician by trade, and thought I knew how diodes worked. One day, I entered university, and it seemed there was more to their life then just a simple bias. They were filled with dopes and holes and what-not. Later, I joined a science forum and probed a bit deeper, into the quantum world of diodes. And being that I had no comprehension of the quantum world, I decided I did not know how diodes worked.
 
  • #100
OmCheeto said:
We're talking about two permanent magnets. No wire involved.

The force and torque on an ideal magnetic dipole (permanent dipoles are the main source of magnetism in permanent magnets, so to understand a magnet you first need to understand an ideal magnetic dipole) can be computed by considering the Lorentz force on a current loop and taking the limit as the loop is shrunk to zero size while its magnetic moment is held constant (Classically, something must hold the magnetic moment constant, and this unkown something is what must do the work when the dipole is placed in an external magnetic field).

Some posters in this thread apparently believe that even classically, magnetic dipoles are fundamentally different than current loops (and according to the links/quotes provided in their arguments, they are not alone in that belief). I would argue that since the dynamics of a dipole are easily computed from the Lorentz force law applied to a current loop, that classically, magnetic dipoles should be treated on the same footing as any other current distribution (and most of the Electrodynamics textbooks I've seen do exactly that). Treating them as being fundamentally different just adds (unnessecarily!) another axiom to the classical theory of Electrodynamics.
 
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