------------------Follow-up of my post #166--------------------
For the following analysis I will restrict myself to mere high school classical physics.
Perhaps the simplest case to model two permanent magnets is two single current loops 1 and 2. Let's assume current loops of 1 m circumference, made of 1 mm diameter wire; distance d between the loops ca.1 cm (diameter << d). As pictured, the currents flow through the wires (---) into the screen on the left (x), and flow out of the screen on the right (0):
1 x----0
2 x----0
Here the wires are attracted to each other by the Lorentz force: F =
Ix
B . L
However, for calculation we can approximate this particular example with two straight wires of 1 m length by opening the loops above the screen and straightening them out:
1 --------->--------- I
1
2 --------->--------- I
2
Now we have the basic configuration of the definition of the Ampere:
F = 2.10-7 I
1 I
2 L / d
For this case I obtain F= 2.10-7 * 100 * 1 / 0.01 = 2 mN.
Suppose that the top magnet is connected to an external mechanism that is actuated by it. We allow the top magnet to move towards the bottom magnet over a small distance, for example from 11 mm to 9 mm. We will assume that the average currents are approximately 1 A (more follows).
Then the work done by the Lorentz force on the top magnet and whatever it is driving, according to [1] and [2]:
F.d ≈ 2.10
-3 * 2.10
-3 J = 4 μJ.
That settles, I think, the question concerning "force doing work" according to the considered literature.
However, in my personal definition not a force but an entity "does work".
In that context, we can distinguish two main cases for the current flow.
1. A common electromagnet, let's say with a current source:
Following Lenz-Faraday-Maxwell we find that the motion will induce an electric field in each wire that opposes the motion; however the current prevents the diminishing of the magnetic field energy. Thus the field provides the acting force but the energy is passing through.
Mechanical equivalent: A spring or rope with which a tractor pulls a trailer.
I would not say that such a thing "does work", but the literature does. I would say that it "transmits work", but that's my beef.
2. For a true permanent magnet there is no external current source.
Following Lenz-Faraday-Maxwell we find that the motion will induce an electric field in each wire that opposes the motion by reducing the currents and the corresponding magnetic fields. Thus the magnetic fields deliver the energy of the magnetic forces that drive the external application.
Mechanical equivalent: A spring that gives off stored energy to drive a clock.
Consequently for the case of a real magnet, not only according to [1] and [2] but also according to my personal definition of "work" the magnetic field "does work", as it loses energy by providing the acting force that does work.
[1]
http://en.wikipedia.org/wiki/Work_(physics)
[2] http://www.lightandmatter.com/html_books/lm/ch13/ch13.html#Section13.1