Measuring Productivity: 2 Main Multifactor Measures

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The discussion centers on two primary multifactor productivity measures: total output divided by the sum of labor, capital, and intermediate inputs, and value added divided by the sum of labor and capital. The original poster questions the validity of a suggested formula by their teacher, which uses value added divided by the total of labor, capital, and intermediate inputs. They argue that this formula does not make sense because intermediate inputs do not contribute to value added. The conversation explores the implications of including intermediate inputs in the denominator, with the poster asserting that if intermediate inputs are removed from the numerator, they should also be deducted from the denominator to maintain consistency. The debate highlights the complexities of measuring productivity accurately and the potential confusion arising from different interpretations of productivity formulas.
luis20
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I found on the internet that there are 2 main multifactor productivity measures:

1) total output / (labour + capital + intermediate inputs)

2) value added / (labour + capital)

, where value added = total output - intermediate inputsThis two measures make sense but my teacher said that if we want total productivity and use value added we should do:

value added / (labour + capital + intermediate inputs)

This measure makes no sense to me, since intermediate inputs do not produce value added.
What do you think?
 
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If you need more intermediate inputs to add the same value, something is worse, so you might want some index to go down.
 
mfb said:
If you need more intermediate inputs to add the same value, something is worse, so you might want some index to go down.

Yes, I would include losses of intermediate inputs in the denominator. But the amount I took from numerator shouldn't I take from denominator too? (since I know that amount is represented in both numerator and denominator)

I mean, if the original ratio is: output / input, then if I take the amount "a" from output, (and "a" is also included in input), I should take "a" from input, so it would be:

(output - a) / (input - a)

and not:

(output - a) / input

right?
 
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value added = total output - intermediate inputs - (other variables)

You already use (output - a) / (input - a) in your formula, where a are intermediate inputs and (output-a) is "value added".
 
mfb said:
value added = total output - intermediate inputs - (other variables)

You already use (output - a) / (input - a) in your formula, where a are intermediate inputs and (output-a) is "value added".

Yes, but my teacher suggested this measure:

value added / (labour + capital + intermediate inputs)

which is:

(output - a) / inputThis is my actually question, is he wrong? ^^
 
If you use "a" as sum of all inputs, it is
(output - input) / input = output/input - 1

That is fine, and the value looks interesting.
 
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