Radiation vector for a short dipole near a perfect magnetic conductor

AI Thread Summary
To calculate the radiation vector produced by a short dipole near a perfect magnetic conductor (PMC), the images method must be adapted from its use with perfect electric conductors (PEC). In the case of a PMC, the image dipole would have an opposite current to achieve zero magnetic field at the boundary. This results in a situation where the radiation vector becomes zero due to the cancellation of the opposite currents. Understanding the differences between PEC and PMC is crucial for accurately applying the images method in electromagnetic calculations. The discussion highlights the complexities involved in transitioning from PEC to PMC scenarios in radiation analysis.
Bromio
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Hi there.

If I wanted to calculate the radiation vector (in z > 0) produced by a short dipole with uniform current Io (+z direction) on a infinite perfect electric conductor (plane z=0), I'd have to apply the images method. So I'd have to calculate the radiation vector produced by two short dipoles, one in z > 0 and one in z < 0, with currents Io.

However, if we change the perfect electric conductor by a perfect magnetic conductor, how can I apply the images method?

Thank you.
 
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Bromio said:
Hi there.

If I wanted to calculate the radiation vector (in z > 0) produced by a short dipole with uniform current Io (+z direction) on a infinite perfect electric conductor (plane z=0), I'd have to apply the images method. So I'd have to calculate the radiation vector produced by two short dipoles, one in z > 0 and one in z < 0, with currents Io.

However, if we change the perfect electric conductor by a perfect magnetic conductor, how can I apply the images method?

Thank you.

What's a perfect magnetic conductor?
 
It's an idealization.

PEC (Perfect Electric Conductor): \hat{n}\times\vec{E}=0 and \hat{n}\times\vec{H}=\vec{J}_s.

PMC (Perfect Magnetic Conductor): \hat{n}\times\vec{E}=-\vec{M}_s and \hat{n}\times\vec{H}=0.

Thank you.
 
At very low frequency, mumetal of permalloy are good magnetic conductors.

It would change the sign of the current in the image. Opposite current achieve zero magnetic field at the magnetic conductor, while same currents achieve zero electric field.
 
Hi.

I understand what you say, but, in that case, radiation vector is 0 (because currents are opposite), isn't it?

Thank you.
 
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