How does an electron carry energy in a circuit?

AI Thread Summary
Electrons carry energy in a circuit primarily through their position, which influences the electric field rather than their kinetic energy. The electric field, generated by the arrangement of electrons, is what devices utilize when connected to a voltage source. Changes in voltage, such as from 6 V to 12 V, affect the electric field and the relative positions of electrons, enabling energy transfer. The concept of virtual photons as force carriers in electromagnetic interactions is complex and not essential for understanding basic circuit energy dynamics. Ultimately, the movement and arrangement of electrons relative to the wire's atomic structure facilitate the flow of electric energy.
4 Ton Mantis
Messages
2
Reaction score
0
By what means does an electron carry energy in a circuit? What physical aspect of the electron is changing under the influence of say 6 V versus 12 V?

Kinetic energy doesn't explain it as electrons at later points in the circuit would be slower and bog down higher-energy electrons in earlier parts of the circuit.
 
Physics news on Phys.org
Maybe think of the electric fields as carrying the energy. That is what your device is 'using' when its hooked up to voltage, its using the electric field and its properties to do work. In this sense the role electrons play is to rearrange themselves so that you get the electric field you want out of the wire. The 'aspect of the electron' that is changing is its position which in turn changes the electric field.
 
That makes sense, thank you. And if you or someone else could refresh my memory: is the electric field generated by exchange of virtual photons between electrons? Or if not, how is it composed?
 
4 Ton Mantis said:
By what means does an electron carry energy in a circuit? What physical aspect of the electron is changing under the influence of say 6 V versus 12 V?
By what means does a boulder carry energy down a hill? By its position (i.e. potential energy due to position).

4 Ton Mantis said:
Kinetic energy doesn't explain it as electrons at later points in the circuit would be slower and bog down higher-energy electrons in earlier parts of the circuit.
Electrons are so light that their KE is completely negligible in most circuits.
 
4 Ton Mantis said:
That makes sense, thank you. And if you or someone else could refresh my memory: is the electric field generated by exchange of virtual photons between electrons? Or if not, how is it composed?

They are the force carriers of the EM interaction, yes. The subject of virtual particles is very complicated and I highly advise you to simply ignore them unless you are dealing with the various Quantum theories that use them.
 
4 Ton Mantis said:
By what means does an electron carry energy in a circuit? What physical aspect of the electron is changing under the influence of say 6 V versus 12 V?

Kinetic energy doesn't explain it as electrons at later points in the circuit would be slower and bog down higher-energy electrons in earlier parts of the circuit.

This is not so easy question.

An electron in the wire feels that other electrons are pushing it, equally from all directions.

If we ask the electrons, if they are carrying energy, they might say: "we are storing electrick energy, and we are moving relative to the atoms in the wire, because the atoms are all moving to the same direction"

If we look at some electrons that seem to be squeezed together, and the electrons seem to be moving to the right, then it is a correct thing to say that electric energy is moving to the right, relative to us.

But, if we start walking to the right, faster than the electrons, then we must say that electric energy is moving to the left, relative to us.
 
I was using the Smith chart to determine the input impedance of a transmission line that has a reflection from the load. One can do this if one knows the characteristic impedance Zo, the degree of mismatch of the load ZL and the length of the transmission line in wavelengths. However, my question is: Consider the input impedance of a wave which appears back at the source after reflection from the load and has traveled for some fraction of a wavelength. The impedance of this wave as it...
Back
Top