Conservative forces and systems

AI Thread Summary
The discussion centers on the classification of gravitational force as conservative or nonconservative. It highlights a misunderstanding regarding the definition of constraint forces, clarifying that gravity is not a constraint force but rather a fundamental force that can do work. The participants emphasize that constraint forces typically do not do work, as they act to impose boundary conditions without moving through a distance. Consequently, the classification of gravitational force as nonconservative based on the initial premise is incorrect. The mechanical energy of a system under gravitational influence remains constant, affirming that gravity is indeed a conservative force in Newtonian mechanics.
Aniket1
Messages
58
Reaction score
2
I read in a book that if the constraint forces do work, the system is conservative, else it's nonconservative. In that case, consider a system of two bodies moving in an elliptical path under gravitational attraction. Since the gravitational force is continuously doing work on the particles, by the above definition, gravitation is a nonconservative force and the system is nonconservative. However, the mechanical energy of the system remains constant and in Newtonian mechanics, gravitation is classifed under conservative force. Can someone explain where am I going wrong.
 
Physics news on Phys.org
Are you counting the kinetic and potential energy of the orbiting object?
 
Yes.
 
What book did you read this in?
 
Aniket1 said:
I read in a book that if the constraint forces do work, the system is conservative, else it's nonconservative. In that case, consider a system of two bodies moving in an elliptical path under gravitational attraction. Since the gravitational force is continuously doing work on the particles, by the above definition, gravitation is a nonconservative force and the system is nonconservative. However, the mechanical energy of the system remains constant and in Newtonian mechanics, gravitation is classifed under conservative force. Can someone explain where am I going wrong.


Gravity is not a constraint force.

The term 'constraint force' is used to describe forces that essentially act to impose boundary conditions. An example is the reaction force of the ground on you, stopping you falling through it.

Generally these forces don't do work, since they don't act through any distance.

So the question of them being conservative or non-conservative is meaningless.
 
Thread 'Gauss' law seems to imply instantaneous electric field propagation'
Imagine a charged sphere at the origin connected through an open switch to a vertical grounded wire. We wish to find an expression for the horizontal component of the electric field at a distance ##\mathbf{r}## from the sphere as it discharges. By using the Lorenz gauge condition: $$\nabla \cdot \mathbf{A} + \frac{1}{c^2}\frac{\partial \phi}{\partial t}=0\tag{1}$$ we find the following retarded solutions to the Maxwell equations If we assume that...
Thread 'A scenario of non-uniform circular motion'
(All the needed diagrams are posted below) My friend came up with the following scenario. Imagine a fixed point and a perfectly rigid rod of a certain length extending radially outwards from this fixed point(it is attached to the fixed point). To the free end of the fixed rod, an object is present and it is capable of changing it's speed(by thruster say or any convenient method. And ignore any resistance). It starts with a certain speed but say it's speed continuously increases as it goes...
Maxwell’s equations imply the following wave equation for the electric field $$\nabla^2\mathbf{E}-\frac{1}{c^2}\frac{\partial^2\mathbf{E}}{\partial t^2} = \frac{1}{\varepsilon_0}\nabla\rho+\mu_0\frac{\partial\mathbf J}{\partial t}.\tag{1}$$ I wonder if eqn.##(1)## can be split into the following transverse part $$\nabla^2\mathbf{E}_T-\frac{1}{c^2}\frac{\partial^2\mathbf{E}_T}{\partial t^2} = \mu_0\frac{\partial\mathbf{J}_T}{\partial t}\tag{2}$$ and longitudinal part...

Similar threads

Back
Top