Does Gauss's Law hold true for a point charge near a sphere?

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A point charge located at x=4 generates an electric field that varies in strength across a sphere centered at the origin with a radius of 3 cm. The electric field is significantly stronger at the near end of the sphere (x=3) compared to the far end (x=-3), leading to a non-zero net flux if calculated directly. However, Gauss's Law still holds true in this scenario, as the total electric field lines entering and leaving the sphere must be considered. The density of electric field lines indicates the strength of the field and the corresponding flux through the surface. Ultimately, despite the varying field strength, Gauss's Law applies, confirming that the net flux through the sphere remains consistent with the law's principles.
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Consider a point charge on the x-axis at x=4. And a sphere with radius 3cm is kept beside the point charge centered at the origin. Consider the near end (x=3) and the far end (x=-3) ... We will find that E from the point charge is much bigger in the close end than E at the far end. So if we calculate inward and outward flux to get the net, this would not be zero since they strike the same area. Does this vilate with Gauss's Law??
 
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When in doubt, do the math. You will (hopefully) find that Gauss's law also applies in this case.
 
The intuition behind this case is as follows:

We think of the electric field as a bunch of arrows (field lines), with the density of them telling you the strength of the field. But they also tell you the flux through a surface, the more arrows, the more flux. If you think about the situation you came up with, how many arrows enter the sphere, and how many leave? (if you have a hard time thinking about this, "follow" a single arrow from the point charge, towards the sphere, and out to infinity. What does it do?) Does this violate gauss' law?
 
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