Initial Velocity: Stone Released from Balloon

AI Thread Summary
When a stone is released from a balloon moving upwards at a constant velocity, its initial velocity is equal to that of the balloon, not opposite. The confusion arises from the assumption that the stone's velocity becomes zero immediately upon release. In reality, the stone continues to move upwards with the same velocity as the balloon at the moment of release. This concept is similar to throwing an object upwards from a moving hand, where the object retains the upward velocity of the hand. Understanding this principle clarifies the dynamics of objects in motion relative to their initial conditions.
manimaran1605
Messages
60
Reaction score
0
A stone released from balloon moving upwards with some constant velocity, the initial velocity of stone is same as the velocity of balloon with opposite sign, but how? What i thought is that the instant stone is released which goes upwards with balloon, stone which is going upwards would stop (t=0) velocity (u=0).
 
Physics news on Phys.org
manimaran1605 said:
A stone released from balloon moving upwards with some constant velocity, the initial velocity of stone is same as the velocity of balloon with opposite sign, but how? What i thought is that the instant stone is released which goes upwards with balloon, stone which is going upwards would stop (t=0) velocity (u=0).

So you're saying that there's NO difference between just releasing the stone from a stationary balloon that isn't moving? Think again.

Zz.
 
  • Like
Likes 1 person
manimaran1605 said:
A stone released from balloon moving upwards with some constant velocity, the initial velocity of stone is same as the velocity of balloon with opposite sign, but how?
No, not opposite sign. Same sign.
What i thought is that the instant stone is released which goes upwards with balloon, stone which is going upwards would stop (t=0) velocity (u=0).
You're free to think whatever you want. That doesn't make it right.
 
manimaran1605 said:
What i thought is that the instant stone is released which goes upwards with balloon, stone which is going upwards would stop (t=0) velocity (u=0).

Think about that for a moment. When you throw a stone upwards, you release it from your hand while your hand is moving upwards rapidly... What happens?
 

Thread 'Derivation of Hamilton's Principle: Questions'

I have recently been really interested in the derivation of Hamiltons Principle. On my research I found that with the term ##m \cdot \frac{d}{dt} (\frac{dr}{dt} \cdot \delta r) = 0## (1) one may derivate ##\delta \int (T - V) dt = 0## (2). The derivation itself I understood quiet good, but what I don't understand is where the equation (1) came from, because in my research it was just given and not derived from anywhere. Does anybody know where (1) comes from or why from it the...
View full post »

Similar threads

A stone is dropped from an ascending balloon...
Replies
10
Views
1K
Find the initial velocity ##U##
Replies
3
Views
865
The gyroscope and its ability to avoid "falling down"
2
Replies
60
Views
6K
B Understanding Momentum: The Relationship Between Mass, Velocity, and Force
Replies
29
Views
3K
Optimal Size of Rocket Engine Nozzle for Vacuum Performance
Replies
26
Views
3K
Can a Stone Remain in Circular Motion if Tension Equals Zero Before Velocity?
Replies
12
Views
3K
Initial Velocity of a dropped object problem
Replies
4
Views
3K
I Is there a way in Lagrangian mechanics to incorporate the inertial response from initial momentum when using initial conditions instead of BCs?
Replies
9
Views
983
B The physics of flywheel launchers (like tennis ball shooters)
2
Replies
60
Views
4K
B Conservation of momentum and conservation of energy details
Replies
30
Views
3K

Hot Threads

Recent Insights

Back
Top