How Much Effort is Needed to Move a 2000 lb Object 50 ft?

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To move a 2000 lb object horizontally, no work is required if friction is ignored, as work is defined by the force applied over a distance. However, if friction is considered, the effort needed depends on the friction coefficient between the object and the surface. For a pallet moved on smooth concrete, the friction coefficient is approximately 0.01 to 0.02, which means calculating the force of friction is essential to determine the effort needed to initiate movement. The discussion emphasizes that understanding the concepts of work and friction is crucial for accurately assessing the effort required. Ultimately, the amount of force needed to get the pallet rolling is directly tied to overcoming friction, not the weight of the person moving it.
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let's say a 180 lbs person needs to move a 2000 lbs object 50 feet. that would take 100,000 ft/lbs. how do you apply that in terms of how much effort it would take from a 180lbs man? divide by 180 and get 555.5? how do you determine the amount of force required to get this object rolling? this doesn't have to be exact, so friction etc doesn't have to be taken into account for my purposes...
 
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I don't see how the person's weight has anything to do with it.
Looks to me like you have learned some formulas, but no concepts!

Moving a 2000 lb. object 50 feet horizontally would not require 100000 ft-lbs of work. Ignoring friction, it would require no work at all. Moving it 50 feet vertically upward would require 100000 ft-lbs of work because it would have acquired 100000 ft-lbs of potential energy.
 
i'm trying to figure out how much effort it takes for a man to pull a pallet of cokes (2000lbs) from one point in a grocery store to another (50ft). if the pallet is moved by a jack with polyurethane wheels across smooth concrete, or tile floors like in wal-mart, the friction coefficient would be

Hardrubber on Concrete f = 0,01 -0,02m

but I'm no math whiz, honestly i suck at most of it... but what's the simplest way to say it would take a guy _ lbs of effort to get this pallet rolling...
 
bump 4 help
 
HINT: Calculate how much work is done by the force of friction.
 
As I said before, if you are moving something horzontally and ignore friction, there will be no work done at all. All the work in this problem depends on the friction.
 
I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks
Essentially I just have this problem that I'm stuck on, on a sheet about complex numbers: Show that, for ##|r|<1,## $$1+r\cos(x)+r^2\cos(2x)+r^3\cos(3x)...=\frac{1-r\cos(x)}{1-2r\cos(x)+r^2}$$ My first thought was to express it as a geometric series, where the real part of the sum of the series would be the series you see above: $$1+re^{ix}+r^2e^{2ix}+r^3e^{3ix}...$$ The sum of this series is just: $$\frac{(re^{ix})^n-1}{re^{ix} - 1}$$ I'm having some trouble trying to figure out what to...
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