Confusion regarding pinch off voltage in a JFET

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Pinch-off voltage in a JFET refers to the drain-source voltage at which the drain-source current becomes nearly constant, indicating saturation. There is confusion surrounding its definition, as it is also described as the gate-source voltage at which there is no drain-source current. For n-channel JFETs, the pinch-off voltage is positive, while the gate-source cutoff voltage (Vgs(off)) is negative and equal in magnitude to the pinch-off voltage. This results in the relationship |Vp| = |Vgs(off)|, highlighting that the only difference is the sign, with Vp being positive and Vgs(off) negative. Understanding these definitions clarifies the behavior of JFETs in their operational regions.
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I can't figure out what actually is the Pich-off voltage of a JFET.
I basically have confusion between these two definitions:
  1. Pinch off voltage is that gate source voltage at which there is no drain-source current
  2. Pinch of voltage is that 'Drain-Source' voltage after which the drain source current becomes almost constant(saturates).
If there is some other accurate definition for pinch off voltage,Please tell me.
Also i want to ask that what is pinch off region?
Thanks
 
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Here you find answer what is pinch off region.
http://www.electronics-tutorials.ws/transistor/tran_5.html

So the proper definition of a Pich-off voltage is
Pinch of voltage is that 'Drain-Source' voltage after which the drain source current becomes almost constant(saturates).
And for n-channel JFET Pich-off voltage is positive. But because Vgs(off) (the gate source voltage at which there is no drain-source current) voltage is negative and by accident equal to the magnitude of the pinch off voltage. Hence:
|Vgs(off)| = |Vp| the magnitude of the pinch off voltage is equal to Vgs(off).
And this is why we can say that |Vp| = |Vgs(off)| but in the same time Vp is a saturation voltage.
But the only difference is the minus sign. Because Vgs(off) is negative but Vp is positive.
 
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