How to Convert Oersted to Tesla?

AI Thread Summary
To convert Oersted to Tesla, the relation 1 A/m = 4π × 10^-3 Oe is used, applicable in both vacuum and matter. For a magnetic field strength of 50 Oersted, it can be converted to A/m using this relation. In vacuum, 1 A/m corresponds to a magnetic flux density of 4π × 10^-7 T. Therefore, the magnetic field strength of 50 Oersted can be calculated and expressed in Tesla. Understanding these conversions is essential for accurate magnetic field measurements.
Amith2006
Messages
416
Reaction score
2
# If the magnetic field is Oersted, how to convert it into Tesla? Suppose the magnetic field is 50 Oersted, in Tesla what is the magnetic field?
 
Physics news on Phys.org
Hello Amith2006,

the following relation for magnetic field strength given in Ampere A/metre m and Oersted Oe holds true for vacuum and matter:

1\,\frac{A}{m}=4\pi\,10^{-3}\,Oe


In vacuum a magnetic field strength of 1\,\frac{A}{m} will lead to a magnetic flux density of 4\pi\,10^{-7}\,T.

Regards,

nazzard
 
Last edited:
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top