How Does Differential Equations Model Drug Distribution in the Bloodstream?

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fluid with 5mg/cm^3 of drug enters bloodsteam at 100cm^3/hr, drug is absorbed by body tissue or otherwise leaves the bloodstream at a rate proportional to the amount present with a rate constant of .4(hr)^-1.

so assuming the drug is always uniformly distrbuted throughout the bloodstream, the differential equation for the amount of the drug that is present at time t is:

What i have done is:
let D(T)=amnt of drug absorbned by the body, at time t (hrs), in mg

so i got dD/dt= rate in - rate out

i have the rate in=100(5) mg/cm^3 or 500 mg/cm^3
and rate out= D(t)/.4

so my equation is dD/dt= 500-D/.4 then i can just you separation of varibles...

what do you all think
 
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Yes, separation of variables will work. You might also note that that is a "linear differential equation with constant coefficients". Either method will work.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...

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