Fusing Deuterium: The Mystery of Ejected Protons/Neutrons

[chemart]

In fusor you react one deuterium with another one. So you should get 4He2. Why does it ejects one proton or neutron from nucleus?

 

[Astronuc]

D + D -> ³He + n or T + p with almost equal probability, rather than ⁴He. It involves various conservation laws (energy, momentum, spin, . . .) and QM.

 

[Rade]

D + D -> ³He + n or T + p with almost equal probability, rather than ⁴He. It involves various conservation laws (energy, momentum, spin, . . .) and QM.

I have a question. The OP asked about fusion of two "deuterium" (which is nucleons plus electrons), but does not your response give results of fusion of two "deuterons" (nucleons without electrons) ? Next, what differences are expected from the two different fusion events (1) fusion of two deuterium atoms and (2) fusion of two deuteron nuclei. Thanks for any clarification.

 

[Rade]

D + D -> ³He + n or T + p with almost equal probability, rather than ⁴He. It involves various conservation laws (energy, momentum, spin, . . .) and QM.

I have another question. As shown in the attached figures, does not the ⁴He appear for a short period of time as an unstable entity ? If so, is it not possible (at least in theory), to stop the process at this intermediate stage, since ⁴He as the "alpha" is very stable ?