Convergence/Divergence of Series: cos(1/n)

  • Thread starter Thread starter rcmango
  • Start date Start date
rcmango
Messages
232
Reaction score
0

Homework Statement



question is if this series converge absolutely, converge conditionally, or it diverges?

here it is: http://img442.imageshack.us/img442/5899/untitled8tn.jpg

Homework Equations



cos1/n

The Attempt at a Solution



not sure where to start, maybe with the limit comparison test or ratio test?
please help. thanks.
 
Last edited by a moderator:
Physics news on Phys.org
\sum_{n=1}^{\infinity} -1^n \cos \frac{1}{n}. First check if the limit at infinity is less than 1. If each term is more than 1, it won't converge. So as we take the limit, Cos 0, its equal to 1. Since its 1, it diverges. So it can't be absolutely convergent.

For an alternating series, the last term has to converge to zero as well, so its divergent as well.
 
Last edited:
thanks for your help.
 
No problemo :)
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...

Similar threads

Replies
3
Views
1K
Replies
4
Views
2K
Replies
6
Views
2K
Replies
4
Views
1K
Replies
14
Views
2K
Replies
11
Views
3K
Back
Top