Higher Chemical Concentration = Higher Temperature of Precipitation. Why?

AI Thread Summary
Higher concentrations of reactant solutions lead to precipitation at higher temperatures due to the relationship between solubility and temperature. As temperature increases, the solubility of products like NaCl and CaSO4 also increases, allowing more solute to dissolve in water. However, higher concentrations can reduce solubility, causing precipitation to occur at lower temperatures. This interplay means that higher concentrations generally yield higher precipitation temperatures. Understanding this concept is crucial for predicting solubility behaviors in chemical reactions.
soggybread
Messages
20
Reaction score
0
If two chemicals are mixed together, say: Na_2SO_4 + CaCl_2 --> 2NaCl + CaSO_4

If I had varying concentrations of the reactant solutions, why is it that the higher concentration mixtures will precipitate at a higher temperature? and lower concentration chemicals will precipitate at a lower temperature?
 
Physics news on Phys.org
Think about how solubility is affected with a change in temperature.
In what situation (higher or lower temperature) will more solute (NaCl and CaSO4) dissolve in the water?
 
what?

Can u explain more clearly
 
As temperature increases solublity of both products increases. But solublity decreases when concentration is increased. At any temperature it is more likely that higher concentration will yield higher precipitation.
 
Thx

So by increasing concentration we are increasing the solubility. By increasing solubility we are lowering the temperature at which the precipitation occurs?

Do you know any website that has the theory behind this?

thx for the reply
 
Thread 'Confusion regarding a chemical kinetics problem'
TL;DR Summary: cannot find out error in solution proposed. [![question with rate laws][1]][1] Now the rate law for the reaction (i.e reaction rate) can be written as: $$ R= k[N_2O_5] $$ my main question is, WHAT is this reaction equal to? what I mean here is, whether $$k[N_2O_5]= -d[N_2O_5]/dt$$ or is it $$k[N_2O_5]= -1/2 \frac{d}{dt} [N_2O_5] $$ ? The latter seems to be more apt, as the reaction rate must be -1/2 (disappearance rate of N2O5), which adheres to the stoichiometry of the...
I don't get how to argue it. i can prove: evolution is the ability to adapt, whether it's progression or regression from some point of view, so if evolution is not constant then animal generations couldn`t stay alive for a big amount of time because when climate is changing this generations die. but they dont. so evolution is constant. but its not an argument, right? how to fing arguments when i only prove it.. analytically, i guess it called that (this is indirectly related to biology, im...
Back
Top