- #1
Hypochondriac
- 35
- 0
I have to solve:
2sinx = cos(x-60), for 0<=x<=360
so far i expanded the cos part
2sinx = cosxcos60 + sinxsin60
as cos60 = 1/2 and sin60 = (sqrt3)/2
2sinx = (1/2)cosx + ((sqrt3)/2)sinx
sinx = cosx + sqrt3 sinx
(1-sqrt3)sinx = cosx
but here's where I'm stuck, i have 2 trig functions in one equation and therefore cannot solve.
2sinx = cos(x-60), for 0<=x<=360
so far i expanded the cos part
2sinx = cosxcos60 + sinxsin60
as cos60 = 1/2 and sin60 = (sqrt3)/2
2sinx = (1/2)cosx + ((sqrt3)/2)sinx
sinx = cosx + sqrt3 sinx
(1-sqrt3)sinx = cosx
but here's where I'm stuck, i have 2 trig functions in one equation and therefore cannot solve.