Sloped Bed Truck: Acceleration & Normal Force?

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When a truck with a sloped bed accelerates horizontally, the normal force on a block resting on the slope decreases due to the truck's acceleration. The initial normal force is calculated as mg*cos x, where x is the slope angle. As the truck accelerates, the normal force is reduced by the term ma*sin x, which can lead to a scenario where the normal force becomes zero if the truck's acceleration is sufficiently high. This indicates that the block may lose contact with the slope if the acceleration exceeds a certain threshold. Understanding these dynamics involves considering an effective gravity in the accelerating frame of reference.
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If I have a truck with a sloped bed in the back, the truck is accelerating horizontally and there's a block sitting on the slope tied to a rope while all this is happening. I was wondering if the trucks acceleration would cause the normal force being applied to the block by the sloped bed to diminish?

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Certainly. If x is the angle between the slope and the horizontal, then initially the normal reaction was mg*cos x. If ‘a’ is the accn of the truck, then the diminished normal reaction is mg*cos x –ma*sin x. Note that the normal reaction could become zero if ‘a’ is high enough. Negative value means that the block is no more resting on the slope because the truck is accelerating so fast.

One way of calculating forces on static objects in accelerating frames is to think that there is an effective gravity of '–a' in that frame, on top of any actual gravity.
 
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