I would like to comment on that famous Afshar experiment, btw.
I had looked at it a long time ago, and I think that the Wiki entry on it is quite well done:
http://en.wikipedia.org/wiki/Afshar_experiment
especially the description of the setup.
What's the idea ? The idea of this experiment is suggested by some handwaving mumbo-jumbo which is unfortunately common in intro quantum courses, the so-called "wave-particle" duality, and other ill-defined concepts.
It's based upon the rather naive "picture" of a photon putting up the hat of a particle sometimes, and the hat of a wave at other times, and this is usually illustrated in intro quantum courses by variations on the 2-slit experiment.
In a 2-slit experiment, it is said (and that's really mumbo-jumbo) that when the two slits are open, and we make no attempt at detecting "which way" the photon went, that it puts up its wave hat, and makes an interference pattern. However, from the moment that we try to trick it into telling us which slit it went through, it puts on its particle hat, and the interference pattern disappears.
This is, IMO, a very naive and very misguiding way of looking at quantum theory, but it is very common to start quantum courses that way, probably to try to make a *didactical* connection with former knowledge by the students, which are acquainted with classical systems of particles (Newtonian mechanics) and of waves (classical EM).
What really happens formally, is that the photon statevector evolves through the setup, and according to changes in the setup, the evolution equation (schroedinger equation) of the statevector is different.
So what happens when one slit is open, is that the state vector takes on the form of a spatial distribution of a "blob" which evolves through the lens onto D1 if slit 1 was open, and on D2 if slit 2 was open. This simply follows from the evolution of the wavefunction, which, in this particular case, is IDENTICAL TO THE MAXWELL EQUATIONS because it is one of those properties that single-photon evolution is identical to classical EM evolution.
This is why this experiment is actually CLASSICAL OPTICS.
If we open both slits, then the wavefunction takes on an interference pattern just before the lens, and refocusses on the two detectors after it.
We have, in this setup, the evolution:
|slit 1> --> |blob1> --> |det1>
|slit 2> --> |blob2> --> |det2>
where the first --> is the evolution through space to just before the lens, and the second --> is the evolution through the lens.
From the superposition principle follows:
1/sqrt(2)(|slit1> + |slit2>) --> 1/sqrt(2)(|blob1>+|blob2>) --> 1/sqrt(2)(|det1> + |det2>)
|blob1> + |blob2> is an interference pattern.
We hence see that if only slit 1 is open, then only det1 will count, if only slit 2 is open, then only det 2 will count, and if slit 1 and slit 2 are open, then we have 50% chance that det 1 will count, and 50% chance that det 2 will count.
Now, let us place the grid. The grid is a projector which let's through entirely the interference pattern:
|blob1> + |blob2> gets through.
But which scatters PARTLY the complementary pattern (with the "peaks" on the wires):
|blob1> - |blob2> is reduced to a (|blob1> - |blob2>) + sqrt(1-a^2) |other>
where |other> stands for a scattering of the light that will not be focussed, nor on detector 1 nor on detector 2 and hence is orthogonal to the |blob1> and |blob2> states.
so its matrix representation in the
|i+> = 1/sqrt(2)(|blob1> + |blob2>) ;
|i-> = 1/sqrt(2)(|blob1> - |blob2>) ;
|other>
basis
is
1 0 0
0 a -sqrt(1-a^2)
0 sqrt(1-a^2) a
Note that because of unitarity, it is impossible for the scattering to scatter into the |i+> state (which is normal, because the i+ state has "darkness" on all the scattering wires).
The coefficient a determines how much of the light of the complementary pattern is actually scattered by the wires and depends on their thickness and so on. If there's not much scattering, then a is pretty close to 1.
If both slits are open, then we have:
1/sqrt(2)(|slit1> + |slit2>) --> |i+> --> |i+> --> 1/sqrt(2)(|det1> + |det2>)
Here the first --> is the evolution through free space, the second --> is the effect of the wires, and the third is the effect of the lens.
If we have only slit 1 open, then we can write this as:
|slit1> =1/sqrt(2) ( 1/sqrt(2)(|slit1> + |slit2>) + 1/sqrt(2)(|slit1> - |slit2>))
using superposition, this becomes:
|slit1> --> 1/sqrt(2) (|i+> + |i->) --> 1/sqrt(2) (|i+> + a |i-> + sqrt(1-a^2) |other>)
--> 1/sqrt(2)(1/sqrt(2) (|det1> + |det2> )+ a/sqrt(2) (|det1> - |det2>) + sqrt(1-a^2) |nodet>)
So we see that we expect to have as end state:
1/2 (1+a) |det1> + 1/2 (1-a) |det2> + sqrt(1-a^2)/sqrt(2) |nodet>
If there is not much scattering (fine wires), then a is close to 1, and we have that we have almost 100% chance to have |det1>, a very small chance to have |det2> and a small chance to have the light scattered elsewhere.
If there is more scattering, then the chances to hit detector 1 are smaller, and the chances to have detector 2 become higher.
At "perfect" scattering (a=0) then detector 1 and 2 have equal chances to click.
So we see here the error in reasoning:
in as much as the wires have an effect (a smaller than 1), the detectors are less and less "reliable" to "tell us through which slit the light came" in the case of a single slit opening.
This remains so when the double slit is open. Even though one would *THINK* that a click in detector 2 means that the light came through slit 2, and a click of detector 1 means that the light came from slit 1, this is not true. The detectors do not indicate reliably anymore from which slit came the light (in as much as the wires do something). Hence there non-scattering effect in the case of the two open slits (symbolised by the perfect transmission of state |i+>) is NOT in conflict with a so-called "which-way" measurement.
But this experiment has a much more classical interpretation.
Indeed, it is simply "mode-coupling". The optical system without grid is simply "2 waveguides": one that goes from slit 1 to detector 1, and one that goes from slit 2 to detector 2. The insertion of the grid couples these two waveguides, and allows for an exchange. The strength of the coupling is given by the scattering intensity of the wires (here written by "a").