Converting engine power into a force

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To accurately calculate a car's top speed, it's essential to translate engine power into the force exerted by the wheels. The relationship between power, force, and speed can be expressed as power equals force times speed. To convert engine torque into wheel force, use the formula: driven wheel force equals wheel torque divided by the effective radius of the tire. Additionally, consider drivetrain and rolling friction losses, typically estimated at around 15%, and calculate aerodynamic drag based on cross-sectional area, drag coefficient, and speed squared. Understanding these relationships is crucial for determining the car's maximum speed effectively.
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I am wanting to accurately calculate the top speed of a car (using it's power, mass, drag, and friction). I started by suming up the forces, but I cannot think of a way to translate the engines power into the force pushing the car forward.
 
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power is energy/time. energy or work, is force*distance. so instantaneous power is force*distance/time, which is force*velocity.
 
Prob. not enough detail. How do I convert the torque of power the engine is sending to the wheel into a force. I thought about t=rF => F=t/r with r being the wheel radius, but that doesn't make sense. So, I need a way to translate the torque/ power the engine is sending to the wheel into a force that the wheels are exerting (sp?) against the ground to move the car forward. Maybe I am going about this problem in the wrong way idk.
 
Power = force times speed.

In English units to calculate horsepower given force and speed:

power/hp = force (lbs) x speed (mph) / 375 (conversion factor).

You can ignore the gearing factor, since it's assumed that you gear the car so peak power occurs at top speed, so the rpm, torques, ... don't need to be known. You'll need to estimate drivetrain and rolling friction losses and reduce the peak power by this amount, usually 15% loss is a good estimate for cars with manual trannys. The next problem is calculating aerodynamic drag, which will be related to cross sectional area times coefficient of drag times speed2.

How do I convert the torque of power the engine is sending to the wheel into a force?
Driven wheel force = wheel torque divided by effective radius of tire. Wheel torque = engine torque times overall gear ratio (times effeciency factor, 85% is a reasonable esitmate).
 
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