A question on the operator e^D

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The discussion centers on the validity of using the operator e^D, where D represents differentiation with respect to x. It is noted that the functions acted upon by this operator must be infinitely differentiable (C^∞) or at least weakly differentiable. While replacing real numbers with operators can be valid in specific contexts, it may lead to incorrect conclusions if the properties of the operators differ from those of real numbers. An example is provided where the commutative property of multiplication does not hold for non-commuting operators. Overall, caution is advised when substituting real numbers with operators in mathematical expressions.
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if D means the derivative respect to x , is always licit to use this operator ??

for example Ramanujan obtained his Master theorem from the integral equality

\int_{0}^{\infty} dx e^{-ax} x^{m-1} = \Gamma (m) a^{-m]

by just replacing the 'a' number by the operator exp(D) and expanding exp(-exp(x) but is this valid ?? , can we always replace real numbers by operators ??
 
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mhill said:
if D means the derivative respect to x , is always licit to use this operator ??

for example Ramanujan obtained his Master theorem from the integral equality

\int_{0}^{\infty} dx e^{-ax} x^{m-1} = \Gamma (m) a^{-m]

by just replacing the 'a' number by the operator exp(D) and expanding exp(-exp(x) but is this valid ?? , can we always replace real numbers by operators ??

For your first questions If you want to use the operator e^D the functions it acts on must certainly be C^\infty or in some other weak sense differentiable an infinite number of times.

To your second question: in this special case it seems to have been correct (maybe not properly justified, though).

Your last question: In principle: yes, but a true statement may become false if you replace numbers by operators. Consider ab=ba which is true for real numbers a und b but not true for non-commuting operators.

Pere
 
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