- #1
futurebird
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Given a circle radius 1 how do you divide it into pieces of equal area using parallel lines?
Maybe find the area under f(x) = \sqrt{1-x^{2}}
OK
\int f(x)dx = \frac{1}{2} \left( x\sqrt{1-x^2} - \sin^{-1} (x) \right)
Well how do you find the location for the cuts if you need to divide the circle into n pieces?
This seems simple enough, but I can't figure it out.
Is there a better way to do this, without calculus?
Maybe find the area under f(x) = \sqrt{1-x^{2}}
OK
\int f(x)dx = \frac{1}{2} \left( x\sqrt{1-x^2} - \sin^{-1} (x) \right)
Well how do you find the location for the cuts if you need to divide the circle into n pieces?
This seems simple enough, but I can't figure it out.
Is there a better way to do this, without calculus?
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