What Factors Affect the Emission of a Photon by an Electron?

AI Thread Summary
The discussion focuses on the factors influencing photon emission by an electron, particularly when the electron's speed decreases upon impact. The energy of the emitted photon is calculated using the equation E_photon = (hc) / lambda, where h is Planck's constant and c is the speed of light. Participants explore the relationship between the electron's kinetic energy, given by 1/2 mv^2, and the energy of the emitted photon, questioning whether to use the initial or halved speed. The conservation of energy principle is emphasized, stating that the initial energy of the electron equals the sum of its final energy and the photon energy. Overall, the discussion delves into the interplay between kinetic energy and photon emission during electron interactions.
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an electron travels at 1 x 106 m/s. when it hits a target, its speed decrease in half and a photo is released. find the phton's wavelength.

so far i know E photon = (hc) / lamda

what about the speed? does the photons' energy same as kinetic energy of the electron which is just 1/2 mv ^2? if so, do i use the halved speed or the initial?
 
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Apply conservation of energy:

E_electron_inital = E_electron_final + E_phton
 

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