What Is the Final Velocity of a 2 kg Mass on a Frictional Incline?

AI Thread Summary
The discussion centers on calculating the final velocity of a 2 kg mass sliding down a frictional incline after being released from a compressed spring. Key points include the mass's initial potential energy, the impact of friction over a specific distance, and the need to correctly calculate the normal force on the incline using the angle of inclination. Participants emphasize the importance of understanding energy conservation, including how much energy is lost to friction. The conversation highlights the formulas for kinetic and potential energy, as well as the method for calculating frictional force. Overall, the thread seeks clarity on energy dynamics in a frictional incline scenario.
Pakbabydoll
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Homework Statement


A spring with a spring- constant 3.4N/ cm is compressed 29cm and released. The 2 kg mass skids down the frictional incline of height 50 cm and inclined at 21 degrees angle.
The acceleration of gravity is 9.8 m/s^2.
The path is frictionless except for a distance of .07 m along the incline which has a coefficient of friction of 0.5.



Homework Equations


I am kind of completely lost.



The Attempt at a Solution


so far this is what I have but its probably wrong anyway

50cos(21)= 46.67902132486
50sin(21)= 17.9183974

N=mg
N= (2)(9.8)= 19.6

Friction= NmK
Friction= (19.6)(0.5)= 9.8

PE= 14.297m
KE= 9.8

Total Energy= 24.097

Problem attached its #6..
Thanks
 

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Pakbabydoll said:
N=mg
N= (2)(9.8)= 19.6
The normal force while on the incline doesn't equal mg.

What's the total energy of the mass initially?

How much energy is dissipated due to work against friction as it slides down?

What's the final energy?
 
Doc Al said:
The normal force while on the incline doesn't equal mg.

What's the total energy of the mass initially?

How much energy is dissipated due to work against friction as it slides down?

What's the final energy?


So to get the normal force on an incline can I use the angle? Would it be like 9.8*cos(21)*2?
and how do you get friction for a specific area?
 
Pakbabydoll said:
So to get the normal force on an incline can I use the angle? Would it be like 9.8*cos(21)*2?
Yes.
and how do you get friction for a specific area?
Just like for anywhere else. Kinetic friction = μN.
 

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