Is Ligand Binding Cooperative and How Many Binding Sites Does the Protein Have?

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AI Thread Summary
The discussion focuses on analyzing ligand binding to a protein at a concentration of 10^-3 M, with specific amounts of bound ligand provided for various concentrations. Participants are attempting to determine if the binding is cooperative, the number of binding sites, and the dissociation constant (K_d) using the Hill equation. There are concerns regarding the accuracy of the plotted graph, which shows inconsistent slopes, complicating the interpretation of the data. Participants suggest ensuring the concentration of free ligand is calculated correctly and recommend organizing data into a table for clarity. Overall, the conversation highlights the complexities in interpreting binding data and the need for precise calculations.
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Homework Statement



The binding of a ligand B to a protein is studied. The protein concentration it 10^-3 M. The amounts bound,b, for each added is given as the following:

(M) (b)(M)
.001 5*10^-6
.002 3.3*10^-3
.005 3.78*10^-3
.007 4.72*10^-3
.01 4.95*10^-3
.02 5*10^-3
.05 5*10^-3

Find if it is cooperative, the number of binding sites, and K_d

Homework Equations



The hills equation can be expressed as log Y/(1-Y) =n log [A] - log K_d


The Attempt at a Solution



So the y intercept is - log K_d and the slope is n when you plot the left side in respect to log [A]. Y is the fractions filled, so I think it would be (b)/(5*10^-3). But, plotting the graph.. it seems a little screwy.. the plot goes from slope of 10.9 to .5 then to ~5.. The graph is shown here.
 
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kittybobo1 said:
So the y intercept is - log K_d and the slope is n when you plot the left side in respect to log [A]. Y is the fractions filled, so I think it would be (b)/(5*10^-3). But, plotting the graph.. it seems a little screwy.. the plot goes from slope of 10.9 to .5 then to ~5.. The graph is shown here.

If it were I could probably help, but I can't see it.:confused:

Possible sources of confusion:
1) [A] in your equation is concentration of free A in solution, did you calculate that?;
2) That's enough possible sources of confusion till I see your graph. :-p

And to make it easier for us and yourself put also the free A in a table with the other parameters.
 
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