How Does Earth's Orbit Affect Light Travel Time?

AI Thread Summary
The discussion centers on calculating how Earth's orbit affects light travel time, specifically using Ole Roemer's observation of Io's delayed appearance. The first part involves determining the distance light travels in 14 seconds, which is calculated to be approximately 4.2 x 10^9 meters. The second part requires finding Earth's speed based on this distance over Io's 42.5-hour orbit, yielding a speed of about 27,451 m/s. For the final part, participants suggest using the orbital radius of 1.5 x 10^8 km to calculate Earth's speed over a year, emphasizing the importance of unit conversion. Overall, the calculations aim to confirm the consistency of Earth's orbital speed with the derived values.
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Homework Statement


Ole Roemer found that the maximum increased delay in the appearance of Io (a moon of Jupiter, I believe) from one orbit to the next was 14 seconds.
a) How far does light travel in 14 seconds?
b) Each orbit of Io is 42.5 h. Earth traveled the distance calculated above in 42.5 h. Find the speed of Earth in km/s.
c) See if your answer for part b is reasonable. Calculate Earth's speed in orbit using the orbital radius, 1.5 x 10^8 km and the period, one year.


Homework Equations


v=d/t


The Attempt at a Solution


a) I got it to be 4.2 x 10^9 m and I'm pretty confident about that answer, so that isn't where I need help.
b) If Earth traveled the same distance as in a) in 42.5 h, I'm assuming I just go V=d/t where the answer is 27451 m/s...
c) For this, I just can't think of the steps. What formula for orbital motion do I need?
 
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Your answers in (A) and (B) look right to me.

C) I think they want you to assume the Earth is moving along a perfectly circular orbit around the sun (its really slightly elliptical, but I think you can ignore that for this question). Using the given radius (distance from Earth to sun), you can calculate the circumference of that circle (orbit). This is the total distance the Earth travels over the given period of a year. You'll need to convert year into its equivalent amount of seconds.

Now you can use: v = d / t

Hint: watch your units

I got an answer that is comparable to the answer in (B) so hopefully that means its right heh.

Hope that helps :)
 
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