What Is the Percent Composition of Magnesium and Aluminum in the Alloy?

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The discussion focuses on calculating the percent composition of magnesium and aluminum in a metal alloy based on the reaction with hydrochloric acid. A 1.00g sample of the alloy produces 0.0989g of hydrogen gas, leading to the need for balanced chemical equations for magnesium and aluminum reactions. The participants clarify that the stoichiometric relationships cannot be directly applied without knowing the specific mole ratios of magnesium and aluminum in the alloy. They suggest creating equations to represent both the total mass of the metals and the total number of moles based on the hydrogen produced. This approach will help determine the composition of the alloy accurately.
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A metal alloy consists of magnesium and aluminum.When a 1.00g sample of the alloy is reacted with excess HCl, 0.0989g of hydrogen gas forms. Calculate the percent composition of the alloy.

Ok I got the following balanced equations :

Mg + 2HCl -> MgCl2 + H2
2Al + 6Hcl -> 2AlCl3 + 3H2

Can I say 1 mole of Mg reacts with 1 Mole of H2, with H2 being 1/4 of 0.0989g and
2 moles of Al reacts with 3 moles of H2, with H2 being 3/4 of 0.0989g?
 
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No, you can't. That will happen only if you will know you have mixture of 1 mole of Mg and 2 moles of Al, you don't know neithe rhow many moles of both nor in waht ratio you have.

Write two equations - one for sum of masses of metals, one for sum of numbers of moles of metals. The latter will use moles of hydrogen produced and stoichiometry of the reactions provided.
 
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