Taylor Expansion of 1/(r-r'): Explained

captainjack2000
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Homework Statement


Could someone please explain how the taylor expansion of 1/(r-r') turns into
( 1/r+(r'.r)/r^3 + (3(r.r')^2-r^2r'^2)/2r^5 +...)


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The Attempt at a Solution

 
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i think it should be \frac{1}{|\vec{r}-\vec{r'}|} yes?

use the 3d taylor expansion formula

\phi(\vec{r}+\vec{a})=\sum_{n=0}^{\infty} \frac{1}{n!} (\vec{a} \cdot \nabla)^n \phi(\vec{r}) with \phi(\vec{r}+\vec{a})=\frac{1}{|\vec{r}-\vec{r'}|}
 
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