Find angular seperation of spectral lines with a grating spectrometer

sailfast775
Messages
2
Reaction score
0

Homework Statement



find the angular separation between the red hydrogen-alpha spectral line at 656nm and the yellow sodium line at 589nm if the two are observed in third order with a 3500-line/cm grating spectrometer.


Homework Equations


maximum equation for multi-slit interference
d sin(theta)=m*lamda

d=distance between two slits
m=the interger called the order (bright spots)
theta=angular seperation
lamda=wavelength

The Attempt at a Solution



I tried plugging all of my data into the equation above with d as 1/grading but I'm not sure if this is the right way to go about the problem. I'm not even sure if this is the best formula to use but I can't find any other relevant equations
 
Physics news on Phys.org
Welcome to Pf sailfast

you are correct, your d is 1/3500 to get centimeters per grating. This equation is correct and applies to this problem. Just be careful with your units and 'm'
 
yay! i rock at PHYS
 
I have the same question here. But when I get sin(theta), I get something over 1. That is not possible. Is my equation wrong? Because I am very sure the units I've been using here are correct. I converted everything into meters.
 

Thread 'Initial conditions for orbits around a wormhole'

Hi, I had an exam and I completely messed up a problem. Especially one part which was necessary for the rest of the problem. Basically, I have a wormhole metric: $$(ds)^2 = -(dt)^2 + (dr)^2 + (r^2 + b^2)( (d\theta)^2 + sin^2 \theta (d\phi)^2 )$$ Where ##b=1## with an orbit only in the equatorial plane. We also know from the question that the orbit must satisfy this relationship: $$\varepsilon = \frac{1}{2} (\frac{dr}{d\tau})^2 + V_{eff}(r)$$ Ultimately, I was tasked to find the initial...
View full post »

Thread 'Please tell me where I am going wrong in this integral'

##|\Psi|^2=\frac{1}{\sqrt{\pi b^2}}\exp(\frac{-(x-x_0)^2}{b^2}).## ##\braket{x}=\frac{1}{\sqrt{\pi b^2}}\int_{-\infty}^{\infty}dx\,x\exp(-\frac{(x-x_0)^2}{b^2}).## ##y=x-x_0 \quad x=y+x_0 \quad dy=dx.## The boundaries remain infinite, I believe. ##\frac{1}{\sqrt{\pi b^2}}\int_{-\infty}^{\infty}dy(y+x_0)\exp(\frac{-y^2}{b^2}).## ##\frac{2}{\sqrt{\pi b^2}}\int_0^{\infty}dy\,y\exp(\frac{-y^2}{b^2})+\frac{2x_0}{\sqrt{\pi b^2}}\int_0^{\infty}dy\,\exp(-\frac{y^2}{b^2}).## I then resolved the two...
View full post »

Similar threads

Diffraction pattern from a grating
Replies
3
Views
843
Calculating the Number of Lines for a Diffraction Grating
Replies
3
Views
2K
Balmer series experiment
Replies
2
Views
953
What Is the Intensity Distribution and Resolving Power of an N-Slit Grating?
Replies
1
Views
2K
Diffraction grating with slits out of phase
Replies
2
Views
4K
How Do Diffraction Gratings Aid in Microscope Magnification?
Replies
6
Views
3K
What is the wavelength difference based on a mini spectrom.?
Replies
1
Views
2K
What Angle Will a Hydrogen Spectral Line Appear in 2nd Order?
Replies
10
Views
3K
Interferometer- 2 spectral lines
Replies
4
Views
2K
Observing Spectral Lines: The Highest Order & Color Sequence
Replies
1
Views
2K

Hot Threads

Recent Insights

Back
Top