Spring Compression from 8.0kg Mass Sliding 7.00m Down 51deg Incline

  • Thread starter Thread starter Ry122
  • Start date Start date
  • Tags Tags
    Extension Spring
AI Thread Summary
An 8.0 kg block slides down a frictionless incline at a 51-degree angle, traveling 7.00 m before compressing a spring. The force exerted by the block upon contact with the spring is calculated to be approximately 60.928 N. The kinetic energy of the block at the moment of contact needs to be determined to find out how much energy is transferred to the spring. The discussion raises a question about the spring constant, which is not provided in the problem. Understanding these factors is essential to calculate the spring's compression accurately.
Ry122
Messages
563
Reaction score
2
block of mass 8.0 kg slides from rest down a frictionless 51degree incline and is stopped by a strong spring with The block slides 7.00 m from the point of release to the point where it comes to rest against the spring. When the block comes to rest, how far has the spring been compressed?

First i determine the force of the block against the spring when it comes in contact with it
9.8cos(90-51)=7.616x8.0=60.928N
and i determine kinetic energy of the block when it comes in contact with the spring.
Then how do i determine how much the force that the block exerts on the spring and how much the kinetic energy that is trasferred to the spring from the block cause the spring to be compressed?
 
Physics news on Phys.org
Is there a spring constant given with the problem?
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top