Troubleshooting a Tank Circuit for 60Hz Frequency Matching

In summary, the speaker is trying to build a parallel LC resonator to filter out a specific frequency, but is experiencing issues with the signal passing through to the ground connection. The capacitor is made from eight polar electrolytic caps arranged in parallel, and the inductor is an iron core toroidal inductor. The impedance of the circuit is calculated to be 0.5 ohm, which is lower than the source's impedance. The expert suggests using a high pass or active band pass filter instead, and provides two suggested tank filters with a frequency sweep from 40 Hz to 80 Hz. The modeling and frequency sweeps were done with LTSpice IV.
  • #1
Idea04
194
1
I have built a parallel LC resonator to tune into a specific frequency. the frequency I am tuning into is 60Hz. The problem I am having is that I matched the value of the inductor and the value of the capacitor to match at that frequency within certain tolerance, And the is no signal being filtered. The frequencies are passing right through to the ground connection. Does anyone know I am doing wrong?
 
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  • #2
There's any number of possible things wrong, but without a schematic I can't even begin to speculate. Including details about what you expect the circuit to accomplish specifically and details about the components used (for example, are the caps aluminum electrolytics, mylar, poly or are the inductors air core, ferrites, tape wound, laminated and which sort of material; silicon steel, 49 material ferrite, etc.) will also be helpful.
 
  • #3
What I'm trying to do is to separate 60Hz from a wide range of frequencies. the capacitor is a non-polar made from eight polar electrolytic caps. arranged in parallel. The inductor is a iron core toroidal inductor. Also according to the calculations the impedance of the circuit is 0.5 ohm far less that the impedance of the source. If that helps.
 
  • #4
Idea04 said:
What I'm trying to do is to separate 60Hz from a wide range of frequencies. the capacitor is a non-polar made from eight polar electrolytic caps. arranged in parallel. The inductor is a iron core toroidal inductor. Also according to the calculations the impedance of the circuit is 0.5 ohm far less that the impedance of the source. If that helps.

You don't make a non-polar capacitor by putting polar capacitors in parallel. You can make a non-polar capacitor of half value by putting two polar capacitors in series, with the "+" ends together, for example. This is done in audio circuits frequently.
 
  • #5
Try recalculating with a reactance of about 200 ohms. O.53 H and 13.26 uF preferably not electrolytic.

Your circuit is basically a short circuit anyway at 60 Hz. The signal source would not be able to deliver the sort of circulating current needed to develop resonance voltages across such low impedance components.

A much better way is to make a high pass filter for 100 Hz rolloff to get rid of 60 hz , or to make an active band pass filter for 60 Hz if you want the 60 Hz.
 
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  • #6
Here are two tank filters suggested above, one a series resonant and the other parallel. with the frequency swept from 40 Hz to 80 Hz. See attached thumbnails. In this case, L=0.53 Henrys, and C = 13.2 microFarads. The impedance is sqrt(L/C) = 200 ohms.
 

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  • #7
Great graphs, Bob S.
Was that done with Spice?

I guess 1 ohm resistance is a bit difficult for a 0.53 H inductance but if it could be held below 20 ohms, to get a Q of at least 10, you would still get reasonable selectivity.
 
  • #8
The circuit modeling and frequency sweeps were done with LTSpice IV, free from Linear Technology Corp.
 

1. What is a tank circuit?

A tank circuit is a type of electronic circuit that consists of a capacitor and an inductor connected in parallel. It is used to store and release energy in the form of oscillations or alternating current.

2. How does a tank circuit work?

A tank circuit works by alternately storing energy in the capacitor and the inductor, and then releasing it back and forth between the two components. This creates a continuous oscillating current in the circuit.

3. What is the resonant frequency of a tank circuit?

The resonant frequency of a tank circuit is the frequency at which the capacitor and inductor are in balance and the circuit oscillates at its maximum amplitude. It is calculated using the formula: f = 1/(2π√LC), where L is the inductance and C is the capacitance of the circuit.

4. What are the applications of a tank circuit?

Tank circuits are commonly used in radio and television transmitters, as well as in electronic oscillators and amplifiers. They are also used in tuning circuits for radio receivers and in signal processing circuits.

5. How can I calculate the values of the components in a tank circuit?

The values of the components in a tank circuit can be calculated using the resonant frequency formula (f = 1/(2π√LC)) and the desired frequency of oscillation. The values of L and C can be adjusted to achieve the desired resonant frequency.

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