Solving for Tension in Elevator Cable: 2300 kg, 50 m, 12 m/s

AI Thread Summary
To solve for the tension in the elevator cable, first calculate the acceleration needed to bring the elevator to rest over a distance of 50 meters. Using the formula for acceleration, determine the value based on the initial velocity of 12 m/s and the stopping distance. Once the acceleration is found, apply Newton's second law to calculate the net force acting on the elevator, which includes both the gravitational force and the tension in the cable. The final tension in the cable can then be derived from these calculations. Understanding both the mathematical and physical components is crucial for solving the problem effectively.
tjbateh
Messages
86
Reaction score
0

Homework Statement


An elevator and its load have a combined mass of 2300 kg. Find the tension in the supporting cable when the elevator, originally moving downward at 12 m/s, is brought to rest with constant acceleration in a distance of 50 m.


Homework Equations





The Attempt at a Solution


Any idea how to approach this problem?
 
Physics news on Phys.org
Hi tjbateh! :wink:

This question is in two parts, a maths part and a physics part.

The maths is to find the acceleration.

The physics is then to find the force.

What is the acceleration? :smile:
 
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Back
Top