Sure, I'd be happy to help you with this proof. First, let's start by assuming that a + a = 0. This means that the sum of a and a is equal to 0. Now, we can use the properties of addition to rewrite this as a + a = a + (-a). This is because the additive inverse of a is -a, meaning that when added together, they cancel each other out and result in 0.
Next, we can use the associative property of addition to rearrange the terms and get (a + a) + (-a) = 0. Now, we know that a + a = 0, so we can substitute this in to get 0 + (-a) = 0. Again, using the additive inverse property, we can rewrite this as (-a) = 0.
Finally, we can use the additive identity property to conclude that a = 0. This is because the additive identity of any number is 0, meaning that when added to any number, it remains unchanged.
Therefore, we have proven that if a + a = 0, then a = 0. I hope this helps with your understanding of this proof. Let me know if you have any further questions.