Calculating Work: Piano Lowering 5m, 2500N Gravity, T1 1830N, T2 1295N

  • Thread starter Thread starter indietro
  • Start date Start date
  • Tags Tags
    Work
AI Thread Summary
The discussion centers on calculating the work done by gravity and two tension forces (T1 and T2) while lowering a piano. The gravitational force acting on the piano is 2500 N, resulting in 12500 J of work done by gravity. T1, with a force of 1830 N, contributes approximately 4575 J of work in the opposite direction. The participant initially miscalculated the work done by T2, which should be around 4579 J, leading to a net work of zero when all forces are considered. The correction highlights the importance of using the correct angle for calculations to ensure accurate results.
indietro
Messages
46
Reaction score
0

Homework Statement


There is a piano that is being lowered 5 m. It has gravity force acting in y-direction (down) of 2500 N. Then it has two ropes attached, they are vectors that are pointing up and out. so T1 is 1830N [W60\circN] and T2 is 1295N [E45\circN]


Homework Equations


so the work by gravity is 12500 J
the work by T1 is 4575 J (opposite direction to work by gravity)

The Attempt at a Solution


so it would make sense that the work by T2 is somewhere close to 7000 J so that the net work is 0. but when i calculate it i get around 4000 J. Can someone check my math...

For T2:
W = Fcos\theta\Deltar
= 1295*cos45*(5)
= 4579 J

? - thnx!
 
Physics news on Phys.org
Hi there,

I believe you have a problem with the angle of T1. Becausem, when I verified your calculations, I come to precisely 0 net work.

Cheers
 
oh yes thank you! i was using an angle that gave the component perpendicular to motion :)
 

Thread 'Rolling without slipping on a curved surface'

Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
View full post »
Thread 'Voltmeter readings for this circuit with switches'

Thread 'Voltmeter readings for this circuit with switches'

TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance) My thoughts for the first case , one of them must be 12 volt while the other is 0 The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...
View full post »
Thread 'Trying to understand the logic behind adding vectors with an angle between them'

Thread 'Trying to understand the logic behind adding vectors with an angle between them'

My initial calculation was to subtract V1 from V2 to show that from the perspective of the second aircraft the first one is -300km/h. So i checked with ChatGPT and it said I cant just subtract them because I have an angle between them. So I dont understand the reasoning of it. Like why should a velocity be dependent on an angle? I was thinking about how it would look like if the planes where parallel to each other, and then how it look like if one is turning away and I dont see it. Since...
View full post »

Similar threads

How Is Work Calculated in a Two-Rope Tension Problem?
Replies
1
Views
5K
Work Done by T1 and T2 in Lowering a Piano
Replies
13
Views
24K
Calculating Work: Lowering a Piano with Two Ropes
Replies
4
Views
9K
How Much Work is Done by Gravity When Lowering a Piano with Two Ropes?
Replies
8
Views
4K
How can net force point in the direction of *negative* work?
Replies
1
Views
4K

Hot Threads

Recent Insights

Back
Top