Electric field with reference to voltage

AI Thread Summary
The discussion centers on the relationship between electric fields and voltage, specifically the equation E = -∇V, which indicates that the electric field direction is opposite to the increase in voltage. It clarifies that a positive voltage corresponds to a positive plate, while the electric field points toward the negative plate, reflecting the movement of positive charges. The confusion arises from interpreting the signs in the context of potential differences, particularly when analyzing a specific potential function. Participants emphasize that the electric field is defined by the gradient of voltage, not emitted by it, and that the negative sign indicates the direction of the field relative to voltage changes. Overall, understanding the gradient and directionality is key to resolving the confusion about electric fields and voltage.
Angello90
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If E=-∇V, does it mean that negative voltage emits positive electric field, and positive v negative ef?
 
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It's basically a matter of definition.
I think you can look at it this way: The field between a positive plate and a negative plate is said to be directed towards the negative plate (the direction in which a positive charge would move) but the positive plate has a positive potential with respect to the negative plate i.e. voltage increases in the opposite direction to the direction of the force on a positive charge.
 
you see I have this question where youre give an equation for potential deference of 10-5z^2, so E= -10z right?, anyway there is a field on one side of the slab (slab is the material with a charge) and it asks about EF on both sides, ie what is EF on right hand side and left hand side. As a hint there is "watch the sign" statement. So I am really confused o_O
 
Angello90 said:
If E=-∇V, does it mean that negative voltage emits positive electric field, and positive v negative ef?

That is not what the Grad means! It is the CHANGE in potential over a distance, i.e. a gradient. In 1 dimension, it is E = -dV/dx.

Zz.
 
Yeah and d(10-5z^2)/dz=-10z, am I correct?
 
Uh?

If you want a simple explanation for the sign, the field points towards the negative side and away from the positive. i.e. a negative slope as distance towards the positive increases - hence the negative sign.
Note. A field isn't "emitted".
 
Ok thanks a lot sophiecentaur, and yeah i know field isn't emitted, that's why i used "emitted" not emmited;) thanks guys
 
Angello90 said:
Ok thanks a lot sophiecentaur, and yeah i know field isn't emitted, that's why i used "emitted" not emmited;) thanks guys

It was terminology I was referring to - not spelling:wink:
 
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