Peskin-Schroeder - Eqn 2.45 derivation

  • Context: Graduate 
  • Thread starter Thread starter giant_bog
  • Start date Start date
  • Tags Tags
    Derivation
Click For Summary

Discussion Overview

The discussion revolves around the derivation of equation 2.45 from Peskin and Schroeder, specifically addressing the terms in the Hamiltonian related to the field operators \(\phi(x)\) and \(\pi(x)\). Participants explore the mathematical identities and boundary conditions relevant to the derivation, focusing on the treatment of certain terms in the commutators.

Discussion Character

  • Technical explanation
  • Mathematical reasoning

Main Points Raised

  • One participant expresses confusion regarding the absence of the \(\frac{1}{2}(\nabla^2[\phi^2])\) term in the \(\pi(x)\) commutator compared to the \((\nabla\phi)^2\) term in the \(\phi(x)\) commutator.
  • Another participant suggests that the missing term is related to a boundary term that is considered to be zero.
  • A further contribution explains the use of integration by parts to handle similar expressions, noting that if a function approaches zero at infinity, certain boundary terms can be neglected.
  • The initial poster acknowledges the clarification and expresses gratitude for the insights provided.

Areas of Agreement / Disagreement

Participants do not explicitly agree on the treatment of the boundary term, but there is a general understanding that it can be neglected under certain conditions. The discussion does not reach a definitive resolution regarding the derivation details.

Contextual Notes

The discussion highlights the dependence on boundary conditions and the assumptions made about the behavior of functions at infinity, which are not fully resolved in the exchange.

giant_bog
Messages
13
Reaction score
0
I'm having problems with the equations leading up to eqn 2.45 on page 25. The hamiltonian has a (\nabla\phi)^2 + m^2 \phi^2 term in the \phi(x) commutator and in the \pi(x) commutator it's \phi(-\nabla^2 + m^2) \phi.

I'm aware of a vector calculus identity that makes (\nabla\phi)^2 = 1/2 (\nabla^2[\phi^2]) - \phi \nabla^2 \phi.

That's almost what we have here, but the \frac{1}{2}(\nabla^2[\phi^2]) term is missing in the \pi(x) commutator.

Did anybody see where it went?
 
Physics news on Phys.org
That's the n-1 boundary term which is taken be zero.
 
You can do this kind of thing using integration by parts. E.g., in one dimension:

\int_{-\infty}^{+\infty} \left(\frac{df}{dx}\right)^2 dx = \left[f(x) \frac{df}{dx}\right]_{-\infty}^{+\infty} - \int_{-\infty}^{\infty}f(x)\frac{d^2 f}{dx^2}dx

And if f(x) goes to zero at infinity then the first term on the right drops out.
 
I see it now. Thanks, folks.
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 41 ·
2
Replies
41
Views
7K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
3
Views
2K
  • · Replies 0 ·
Replies
0
Views
1K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 1 ·
Replies
1
Views
976