How Do You Calculate the Closest Point of Approach for Two Moving Objects?

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To calculate the closest point of approach for two moving objects, start by writing the equations of motion for each object based on their initial positions and velocities. Use the distance formula, which is the square root of the sum of the squares of the x and y coordinates. To find the minimum distance, differentiate the distance function with respect to time and set the derivative equal to zero to solve for time. The discussion highlights the importance of understanding motion equations and differentiation in solving the problem. This approach effectively determines when the two objects are closest to each other.
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Homework Statement


Two objects 1 and 2 are moving towards each other, 1 along the x-axis and the 2 along the y axis. Initially, object 1 is at (- 28.9,0) (in m) moving at speed v 1 = 13.7 m/s, while 2 is at (0.-36.8) (in m) moving at speed v 2 = 7.5 m/s. How long does it take until the objects are at the minimum distance from each other? (give your answer in s)


Homework Equations


I just don't know where to start from... like all i need is a hit or formula. I have no clue how to find the closest poing of approach.


The Attempt at a Solution




*Btw i am new to the forum and this is the first time i am posting something. So, if i make any errors, kindly tell me.

Regards,
Nihant
 
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write the equation of motion for each partile, i.e. x0+v1t, etc.
and use the distance equation sqrt(x^2 + y^2). then...
 
Thank you very much. I figured it out...and then you differentiate it and put it equal to 0 and solve for t...Thanks ;-)
 
You're very welcome, Nikieme
 

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