What is the next five numbers is this sequence:

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The sequence presented consists of fractions that appear to follow a pattern. Participants suggest that it may be a basic arithmetic sequence, prompting the need to identify a common difference. There is a reminder for users to adhere to forum guidelines when posting homework-related questions. The discussion emphasizes the simplicity of the problem, indicating that it can be solved with minimal effort. Identifying the next five numbers in the sequence hinges on recognizing this arithmetic progression.
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(23)/(24), (11)/(12), (21)/(24),(5)/(6), (19)/(24), (3)/(4)
 
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mookiegodiva1 said:
(23)/(24), (11)/(12), (21)/(24),(5)/(6), (19)/(24), (3)/(4)
Is this a homework problem? If so, you need to show what you have tried to do to solve it.
 
Also, please refer to the homework section in the forums for more info on posting homework problems.
 
mookiegodiva1 said:
(23)/(24), (11)/(12), (21)/(24),(5)/(6), (19)/(24), (3)/(4)

This is pretty basic fractions. You can figure this out with very little effort.
 
(Thread moved to HH,Pre-Calc & OP pinged).
 
This is a simple arithmetic sequence.
Can you find the common difference? :)
 
I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks
Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks
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