Calculating Percentage of Stannous Fluoride in Toothpaste Sample

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To calculate the percentage of stannous fluoride (SnF2) in a 10.000g toothpaste sample, the precipitate of stannous phosphate (0.145g) must be used in conjunction with stoichiometry. The approach involves converting the mass of the precipitate to moles, applying the balanced chemical equation to find the mole ratio, and then determining the mass of SnF2 that corresponds to the precipitate. This mass is then divided by the total sample mass (10.000g) and multiplied by 100% to find the percentage. Understanding that not all of the 10.000g is reactants is crucial for accurate calculations.
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Homework Statement


A 10.000g sample of toothpaste containing stannous fluoride gives a 0.145g precipitate of stannous phosphate. What is the percentage of SnF_2 in the toothpaste sample?

Homework Equations



(Actual yield)/(Theoretical yield) * 100%

3SnF_{2}_{(aq)} + 2K_{3}PO_{4}_{(aq)} \rightarrow Sn(PO_{4})_{2}_{(s)} + 6KF_{(aq)}

The Attempt at a Solution



I am not positive what they are asking here. I understand that they want me to use the above formula (the percent one) to find the % composition of a certain molecule in the substance. I am thinking that they want me to first use the 10.000g to calculate the theoretical yield of the stannous fluoride using basic stoichometry and then divide the given mass of product (the precipitate) by that to get a number as a percent. Is that the correct approach?

Thanks

Edit, something is up with the LaTeX here, there should be a formula for calculating the percent (X/Y *100%) and the chemical equation, i don't know why it's rendering like it is with 2 of the chemical formulas. If you click the top equation you will see what I mean.
 
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The question has no complications. Start working backward from the mass of precipitate. Be sure to balance the reaction and then you will have mole ratios from this.
 
Ah, I see what you mean. The 10.000g is the total of both the reactants on the left side of the EQ. So I start with the precipitate, convert to moles, then use a mole ratio to get that in terms of the desired molecule, and convert back to grams using that mass over the 10.000 grams to form the percent equation.

For some reason I kept thinking of the 10.000g as the starting value, probably because every other problem we have done is formed that way.

Thanks alot!
 
Most of what you say is correct. Be sure you understand that most of your 10 gram sample IS NOT THE REACTANTS; only some of it is. The question asks essentially, what proportion of the 10 grams sample of toothpaste was stannous fluoride?
 
I get that, so when I work the product out to using the molar ratio to the questioned reactant, I would put the reactant over the whole mass of the product side. In this case over 10 grams to get the percent. Thanks
 
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