Solve Order of Operations: x= 48÷2(9+3)

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The discussion revolves around solving the expression x = 48 ÷ 2(9 + 3) and highlights the confusion stemming from the order of operations. Participants emphasize the importance of following the order of operations consistently, noting that different interpretations can lead to varying answers. The ambiguity of the expression is a key point, as it can be unclear whether 48 is divided by just 2 or by the product of 2 and 12. It is recommended to use parentheses for clarity, such as writing 48/(2 * 12) to specify the intended order of operations. The conversation underscores the necessity of clear notation to avoid misinterpretation in mathematical expressions.
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Homework Statement


okay. So here is the problem:

x= 48÷2(9+3)


Homework Equations





The Attempt at a Solution



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So, what I am thinking, is how should the order of operation should be followed. There are different answers when tried using a different order of solving. So, could you please help me?
 
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The method on the right more closely follows the rules for order of operations. It does begin by changing the division to the equivalent multiplication. After that it does the operations in an order consistent with the rules for order of operations.

The method on the left uses some properties of equations to rewrite the equation as an equivalent equation in a number of its steps. It also makes use of the associative law and does some rather fancy division of fractions. (It's fancy if you're asking this basic a question.) All the steps are the result of legal algebraic operations, so you get the correct result for x.
 
The order of operations should be followed, period. I'm confused that you said that you get different answers, but the two attempts you attached give you the same answer.

If you did a search, you would have found this thread, which has the exact same question:
https://www.physicsforums.com/showthread.php?t=488334"

I suggest you read this thread.
 
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eumyang said:
The order of operations should be followed, period. I'm confused that you said that you get different answers, but the two attempts you attached give you the same answer.

If you did a search, you would have found this thread, which has the exact same question:
https://www.physicsforums.com/showthread.php?t=488334"

I suggest you read this thread.

Yeah. I have found that thread. But, with so many words and posts, I'm very much confused on which to follow.
 
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To summarize that very long thread, expressions such as 48÷2(9+3) should be avoided because of their ambiguity; namely, is 48 being divided by just 2, or is it being divided by [2 * 12]?

To make matters worse, two different calculator models from the same company yield two different answers for the same expression.

To avoid this problem use parentheses to indicate clearly what you're dividing by. If you mean
\frac{48}{2 \cdot 12}

write it as 48/(2 * 12)

Here the parenthese make it clear that the multiplication should occur before the division occurs.
 
I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks
Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks
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