Find the constant of vain (wien)

  • Thread starter Thread starter stunner5000pt
  • Start date Start date
  • Tags Tags
    Constant
AI Thread Summary
To find the Wien constant from the given spectral radiancy equation, one must differentiate R with respect to wavelength and set the derivative to zero to identify the wavelength at which blackbody radiation is maximized. The relationship w = λ_max T is established, where λ_max is the wavelength corresponding to maximum radiation. Substituting numerical values for constants allows for evaluation and comparison with the known Wien constant of 2898 μm K. The discussion emphasizes that while the process may seem complex, it is manageable with modern calculators. The conversation also briefly touches on a separate inquiry regarding Einstein's theory of specific heat.
stunner5000pt
Messages
1,443
Reaction score
4
Find a wien constant A from the equation R(\lambda,T) = \frac{2\pi h c^2}{\lambda^3} \frac{1}{e^\frac{hv}{kT} - 1} Show that the Wien constant w = Lambda T = hc / 4.965k

Also i know that w = 2898 micro metres Kelvin

I'm not sure what to do here... Do i fiddle with the equation for hte spectral radiancy?? Do i expand the tern for the exp function?

But how would you manage to get the Boltzmann constant in the denominator without expanding the exp function?

Please do help with this!

Part 2 of this question is

Substitute numerical values for the constants and evalute. Compare the result with the Equation of w = 2898 \mu m K

Now i need to solve the first part to get this second part, i would really really appreciate your help on this matter!

Thank you in advance for this!
 
Physics news on Phys.org
The Wien constant is defined as the product of the temperature and the wavelength for which the blackbody radiation is a maximum:

w = \lambda_{max} T

so what you need to do is take the derivative of R with respect to \lambda[/tex], set it equal to 0 and solve for \lambda_{max}. Remember that \nu depends on \lambda. Once you find that value just multiply it by the temperature and you have Wien&#039;s constant!<br /> <br /> It&#039;s actually easier than it looks at the outset! (It might be easier to work with \nu and switch back to wavelength at the end.)
 
Tide said:
The Wien constant is defined as the product of the temperature and the wavelength for which the blackbody radiation is a maximum:

w = \lambda_{max} T

so what you need to do is take the derivative of R with respect to \lambda[/tex], set it equal to 0 and solve for \lambda_{max}. Remember that \nu depends on \lambda. Once you find that value just multiply it by the temperature and you have Wien&#039;s constant!<br /> <br /> It&#039;s actually easier than it looks at the outset! (It might be easier to work with \nu and switch back to wavelength at the end.)
<br /> <br /> Wow i would never think it was that easy! But thank you very much!<br /> <br /> Could you also help me with another one ?? Please?<br /> This one has to do with Einstein&#039;s heory for specific heat<br /> <a href="https://www.physicsforums.com/showthread.php?t=49792" class="link link--internal">https://www.physicsforums.com/showthread.php?t=49792</a>
 
w corresponds to the value of \lambda for which R is a maximum. This maximum occurs at \lambda = w/T.

To find the maximum you just put

\frac{\partial R}{\partial \lambda} = 0

and solve.

The problem is that you can only solve this numerically, since you get a transcendental equation. Good luck.
 
James,

Yes, but that's not a serious problem with modern calculators!
 
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top