AS Mathematics - Core 1 - Indices Problems

AI Thread Summary
The discussion revolves around solving a mathematics indices homework problem involving the expression 25^{1/2} - \frac{5^{-4}}{5^{-5}}. The initial solution correctly identifies that 25^{1/2} equals 5 but struggles with the subsequent calculations, leading to confusion over the final form of the answer. Participants emphasize the importance of using improper fractions instead of mixed numbers for clarity. Additionally, guidance is provided on how to properly format exponents in forum posts using the available tools. The thread highlights common challenges in understanding indices and the need for clear communication in mathematical expressions.
novamatt
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I am struggling with my mathematics indices homework. I think I have some correct answers so far but I'm pretty stumpted on some others. How would I go about solving the following equations.

Homework Statement


1) 25 to the \frac{1}{2} - \frac{5 to the -4}{5 to the -5}


Homework Equations





The Attempt at a Solution


1) 25 to the \frac{1}{2} = \sqrt{25} = 5 i know that
i get lost on the next bit... i end up with
\frac{-625}{-3215} and therefor
5 - \frac{1}{5} = 4\frac{4}5{} but this is not in index form?? if i take it further...
\sqrt[5]{4} to the 4 and from there i have no idea how to go further, plus i am positive I've gone wrong at a much earlier stage.
 
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novamatt said:
I am struggling with my mathematics indices homework. I think I have some correct answers so far but I'm pretty stumpted on some others. How would I go about solving the following equations.
Edited to make readable.
novamatt said:

Homework Statement


1) 25^{1/2}- \frac{5^{-4}}{5^{-5}}


Homework Equations





The Attempt at a Solution


1) 251/2 = \sqrt{25} = 5 i know that
i get lost on the next bit... i end up with
\frac{-625}{-3215} and therefor
5 - \frac{1}{5} = 4\frac{4}5{} but this is not in index form?? if i take it further...
\sqrt[5]{4} to the 4 and from there i have no idea how to go further, plus i am positive I've gone wrong at a much earlier stage.
 
Use the fact that a-n = 1/an.

Also, at this stage in mathematics, we pretty much never write things like 4 \frac{4}{5}. It looks too much like 4 * 4/5. Instead of mixed numbers like this, improper fractions such as 24/5 are preferred.
 
thanks for the assistance its a bit late for me to crack on with the problem at the moment I will return tomorrow and have another go.

Could you please tell me how you put the 1/2 index power or direct me to a link where I can learn how to do this... is it simply html code like the ones provided on your symbol toolbar?
 
You can write exponents, as we in the US call them, by clicking Go Advanced, which opens another menu. Use the X2 button to make exponents.
 
I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks
Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks
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