Amount of Energy from Bullet fired from different weapon

  • Thread starter Thread starter abrowaqas
  • Start date Start date
  • Tags Tags
    Bullet Energy
AI Thread Summary
The energy of a bullet fired from a gun and a rifle with the same linear velocity is theoretically equal, calculated using the formula E = ½·m·v². However, a rifle bullet may possess slightly more energy due to additional rotational energy. The rifle's design allows for greater accuracy and distance, not solely due to energy but also because it experiences less air resistance. This reduced tumbling contributes to its superior performance compared to bullets fired from guns. Overall, while the energy may be similar, other factors influence the effectiveness of the bullets.
abrowaqas
Messages
113
Reaction score
0
How we differentiate the amount of Energy of a bullet fired by a gun and a rifle with same linear velocity?

do they posses the same energy ? or rifle has more energy than gun.
 
Physics news on Phys.org
The energy of the bullet would be E = ½·m·v²

So for the same m and v the energy would be equal, regardless of how the bullet was fired.
 
hi abrowaqas! :smile:
abrowaqas said:
How we differentiate the amount of Energy of a bullet fired by a gun and a rifle with same linear velocity?

the rifle bullet will have very slightly more energy, since it will also have rotational energy

it travels further (and is more accurate) not because of its energy, but because it tumbles less than the gun bullet, and so has less air resistance :wink:
 
Thread 'Gauss' law seems to imply instantaneous electric field'

Thread 'Gauss' law seems to imply instantaneous electric field'

Imagine a charged sphere at the origin connected through an open switch to a vertical grounded wire. We wish to find an expression for the horizontal component of the electric field at a distance ##\mathbf{r}## from the sphere as it discharges. By using the Lorenz gauge condition: $$\nabla \cdot \mathbf{A} + \frac{1}{c^2}\frac{\partial \phi}{\partial t}=0\tag{1}$$ we find the following retarded solutions to the Maxwell equations If we assume that...
View full post »

Thread 'Do electron density waves accompany EM waves in coaxial cables?'

Maxwell’s equations imply the following wave equation for the electric field $$\nabla^2\mathbf{E}-\frac{1}{c^2}\frac{\partial^2\mathbf{E}}{\partial t^2} = \frac{1}{\varepsilon_0}\nabla\rho+\mu_0\frac{\partial\mathbf J}{\partial t}.\tag{1}$$ I wonder if eqn.##(1)## can be split into the following transverse part $$\nabla^2\mathbf{E}_T-\frac{1}{c^2}\frac{\partial^2\mathbf{E}_T}{\partial t^2} = \mu_0\frac{\partial\mathbf{J}_T}{\partial t}\tag{2}$$ and longitudinal part...
View full post »

Similar threads

I Relationship between Concentration of a Force and Energy Density
Replies
11
Views
1K
B When a bullet is fired from the back of train
Replies
28
Views
4K
B Gun Recoil: Will Wall Impact Momentum & Velocity?
Replies
30
Views
3K
I Gyroscopic precession of a spin-stabilized bullet
Replies
10
Views
3K
I Why do bullets precess in the opposite way from gyroscope diagrams?
Replies
23
Views
3K
I Does Reducing Reciprocating Mass in Firearms Affect Recoil?
Replies
10
Views
5K
Gun with a tachyon bullet paradox
Replies
2
Views
2K
Solving the Problem: A Bullet is Fired Horizontally Aiming at an Object
Replies
6
Views
3K
I How fast does a blastwave travel?
5
Replies
236
Views
13K
How Does Bullet Drop Compare to Gravity in Long Range Shooting?
Replies
17
Views
4K

Hot Threads

Recent Insights

Back
Top