Covariant Derivative derivation.

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SUMMARY

The discussion focuses on the derivation of the covariant derivative using the Leibniz rule, specifically demonstrating that \(\nabla_c X_a = \partial_c X_a - \Gamma^{b}_{ac}X_{b}\). The key equation utilized is \(\nabla_{c}X^{a}=\partial_{c}X^a+\Gamma_{bc}^{a}X^b\). The participant successfully integrates the scalar field \(\Phi\) into the derivation, confirming its relevance in achieving the desired result. The conversation highlights the importance of understanding the relationship between covariant derivatives and scalar fields in the context of general relativity.

PREREQUISITES
  • Understanding of covariant derivatives in differential geometry
  • Familiarity with the Leibniz rule in calculus
  • Knowledge of Christoffel symbols and their role in tensor calculus
  • Basic concepts of scalar fields in physics
NEXT STEPS
  • Study the properties of Christoffel symbols in general relativity
  • Learn about the implications of covariant derivatives on tensor fields
  • Explore the role of scalar fields in general relativity
  • Investigate the applications of the Leibniz rule in advanced calculus
USEFUL FOR

This discussion is beneficial for students and researchers in theoretical physics, particularly those studying general relativity and differential geometry. It is also useful for mathematicians focusing on tensor calculus and its applications in physics.

T-chef
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Homework Statement


Using the Leibniz rule and:
\nabla_{c}X^{a}=\partial_{c}X^a+\Gamma_{bc}^{a}X^b
\nabla_{a}\Phi=\partial\Phi

Show that \nabla_c X_a = \partial_c X_a - \Gamma^{b}_{ac}X_{b}.
The question is from Ray's Introducing Einsteins relativity,

My attempt:
\nabla_c(X^aX_a)=\nabla_c(X^a)X_a+X^a\nabla_c(X_a)
= (\partial_{c}X^a+\Gamma_{bc}^{a}X^b)X_a+X^a\nabla_c(X_a)

From here I'm not sure how to introduce the scaler field phi, or how doing so would help. Cheers for any help!
 
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You already introduced it!
 
Of course! The left hand side is exactly the scaler field I need. All comes out nicely after that! Thank you sir,
 

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