Piecewise Linear Modeling (diode)

AI Thread Summary
The discussion focuses on using piecewise linear modeling to estimate the diode voltage in a Thevenin circuit with a square wave input. The diode's turn-on voltage is approximated at 0.7V, and participants explore the appropriate values for diode current and resistance. One contributor suggests starting with a diode current of 1mA, but later realizes that a more logical choice is 0.3mA, leading to a dynamic resistance of approximately 83Ω. The calculated diode voltage for the high state of 1V is found to be around 725mV. The conversation emphasizes the graphical method for determining the operating point by plotting the voltage source and diode characteristics.
hogrampage
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Homework Statement


A pn junction diode is connected to a Thevenin circuit consisting of a 0-to-1V, 1kHz square wave and 1kΩ resistor. Use piecewise linear modeling to estimate the diode voltage for the low (0V), and high (1V) states of the voltage source. Assume the diode to have an approximate turn-on voltage of 0.7V for small currents.


Homework Equations


rd = \frac{nV_{T}}{I_{D}}
iD = \frac{V_{th}-V_{f}}{R_{th}+r_{d}}
VD = Vf + iDrd


The Attempt at a Solution


I was thinking of just picking ID = 1mA, n = 1, and VT = 25mV so that:

rd = 40Ω

I don't know if I'm going about this right, or even where to go next.
 
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For the 1V case...

Are you familiar with the graphical method of finding the operating point? Plot a graph with two "curves" on it:

First one for the voltage source/resistor: Plot open circuit voltage, short circuit current and join with straight line.

Another for the diode, in particular the equation VD = iDrd + Vf is of the form y = mx + c ... a straight line.

Where they cross is your answer.
 
hogrampage said:

Homework Statement


A pn junction diode is connected to a Thevenin circuit consisting of a 0-to-1V, 1kHz square wave and 1kΩ resistor. Use piecewise linear modeling to estimate the diode voltage for the low (0V), and high (1V) states of the voltage source. Assume the diode to have an approximate turn-on voltage of 0.7V for small currents.

The Attempt at a Solution


I was thinking of just picking ID = 1mA, n = 1, and VT = 25mV so that:

rd = 40Ω

I don't know if I'm going about this right, or even where to go next.

Picking iD = 1 mA is definitely not a good idea.

You know VD will be close to 0.7V. So what is a logical choice for iD if the input to the 1K resistor is 1V?
 
With that info, I found iD to be 0.3mA. Then, rd is ~83Ω with n=1 and VT=25mV. So, when the voltage source is 1V:

VD=0.7+(0.0003)(83)=725mV
 
Assuming the piecewise-linear approximation they have in mind is a straight line along the V axis (iD=0) up to V = 0.7V and then a straight line of slope 1/rd up to the operating point iD ~ 0.3 mA, then that would be correct.
 
Alright, thanks :D.
 

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