Calculating the Kinetic Energy of a Meteor: What Factors Influence its Velocity?

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The kinetic energy of a meteor can be calculated using the formula E=1/2 mv², where m is the mass and v is the velocity relative to Earth. Typical meteor velocities range from 10 to 30 km/s, with the minimum velocity being around 11 km/s, which corresponds to Earth's escape velocity. Objects from the outer solar system can achieve higher speeds, potentially up to 75 km/s, though this is rare. The relative velocity of meteors can be influenced by their orbital paths, with comets exhibiting varying speeds based on their prograde or retrograde orbits. Understanding these factors is crucial for accurately determining a meteor's kinetic energy.
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How can I calculate kinetic energy of a meteor? On what variables it depends?

Thanks and sorry for my bad English.
 
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You can use the usual formula for kinetic energy: ##E=\frac{1}{2}mv^2## with the mass m and the velocity v (relative to earth). Typical velocities are 10 to 30 km/s.
 
I thought meteors were faster. :smile:
 
Well, ~11km/s is the minimal velocity, and corresponds to the escape velocity of earth. ~30km/s is the orbital velocity of earth, but most objects nearby have similar orbits, so their relative velocity is lower. Objects from the outer solar system can have higher relative velocities, up to ~75km/s should be possible (but really rare). To get even more speed, you need objects not bound to the solar system.
 
tade said:
I thought meteors were faster. :smile:
30 kms/second is pretty damn fast. That would get them from space to ground in about 3 seconds, if they came in vertically and were not slowed by air resistance.
 
as mbf said 'relative velocity' . comets can have either a prograde or retrograde orbit. so the approach speed of a retrograde is going to be pretty high...
also taking into account keplers second(?) law ...the comet will be most likely at its perihelion when approaching the Sun and so will have an increased speed.
 
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