pyroknife said:
Is ground at 0, simply to put the flat part (where the sine wave signal is 0) at 0 mark on the oscillioscope display?
Here we have an example of a phrase whose meaning is understood by the person who used it, but is clouded in ambiguity to those who haven't experienced it previously.
My best guess is that it means with the AC/DC switch set to "DC". Let me explain why.
When the switch is in the "DC" position, the CRO displays the full input waveform, the whole signal, all of it, with nothing missing. But there are times when you'd like to examine just the alternating part, to amplify it more, and on those occasions you can switch the AC/DC switch to "AC". In the AC position, any DC component is removed, and the zero volts line is moved to where the
average value of your input signal lies. So if your waveform has a ripple or alternating part, the average of this is moved to the zero volts line. In this situation, the waveform has an area above the zero line equal to the area below that zero line. In effect, you lose track of where true zero is.
To determine the average (i.e., by definition, the DC value) of any waveform, switch it between "AC" and "DC" and the amount of shift in the displayed waveform equals the average value of that signal.
Remember, in position "DC" you always see the complete waveform, so you will usually want to start with that position to establish in your mind the full picture of the signal your CRO leads are connected to.