Electric Flux on the surface of a sphere

NWNINA
Messages
7
Reaction score
0

Homework Statement



I'm trying to figure out an equation for finding the net flux that abandons the surface of a sphere which contains a line charge distribution an a charge density. The problem is:

A line charge distribution of 0.6m long with a charge density equal to 5C/m, is contained inside a sphere with radius of 5m. Find the net flux that abandons the surface of the sphere.

Homework Equations



What I have done is the following
ψ=DA
D= εE
ψ=εEA=ε(ρ/(2∏εr)(4∏r^2)
∴ψ =2 ρ r

The Attempt at a Solution



ψ= 2(5C/m)(5m) = 50C

I really don't know if this is the correct approach. Any help would be great.
 
Last edited by a moderator:
Physics news on Phys.org
So I've decided to take a different approach
ψ= ∫∫∫ ρ rdrd∅dθ
not sure if i should use d∅ or dz. maybe the first one because it is spherical.
what limits should I use?
 
NWNINA said:

Homework Statement



Im trying to figure out an equation for finding the net flux that abandons the surface of a sphere which contains a line charge distribution an a charge density. The problem is:

A line charge distribution of 0.6m long with a charge density equal to 5C/m, is contained inside a sphere with radius of 5m. Find the net flux that abandons the surface of the sphere.


Homework Equations



What I have done is the following
ψ=DA
D= εE
ψ=εEA=ε(ρ/(2∏εr)(4∏r^2)
∴ψ =2 ρ r

The Attempt at a Solution



ψ= 2(5C/m)(5m) = 50C

I really don't know if this is the correct approach. Any help would be great.
Use Gauss's Law.

Calculating the flux directly by means of a surface integral will be a mess.
 
Hi, I had an exam and I completely messed up a problem. Especially one part which was necessary for the rest of the problem. Basically, I have a wormhole metric: $$(ds)^2 = -(dt)^2 + (dr)^2 + (r^2 + b^2)( (d\theta)^2 + sin^2 \theta (d\phi)^2 )$$ Where ##b=1## with an orbit only in the equatorial plane. We also know from the question that the orbit must satisfy this relationship: $$\varepsilon = \frac{1}{2} (\frac{dr}{d\tau})^2 + V_{eff}(r)$$ Ultimately, I was tasked to find the initial...
##|\Psi|^2=\frac{1}{\sqrt{\pi b^2}}\exp(\frac{-(x-x_0)^2}{b^2}).## ##\braket{x}=\frac{1}{\sqrt{\pi b^2}}\int_{-\infty}^{\infty}dx\,x\exp(-\frac{(x-x_0)^2}{b^2}).## ##y=x-x_0 \quad x=y+x_0 \quad dy=dx.## The boundaries remain infinite, I believe. ##\frac{1}{\sqrt{\pi b^2}}\int_{-\infty}^{\infty}dy(y+x_0)\exp(\frac{-y^2}{b^2}).## ##\frac{2}{\sqrt{\pi b^2}}\int_0^{\infty}dy\,y\exp(\frac{-y^2}{b^2})+\frac{2x_0}{\sqrt{\pi b^2}}\int_0^{\infty}dy\,\exp(-\frac{y^2}{b^2}).## I then resolved the two...
Back
Top