- #1
Someone2841
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- 6
I wrote up a proof for the continuity of y^2 for practice. Is this acceptable in the context of a Real Analysis I course?
QED
Thanks!
Thanks!
Office_Shredder said:Case one is only taken care of when epsilon is big, which is the uninteresting case. The fact that delta is not a function of epsilon should be an immediate giveaway that you haven't constructed a proof
You need a < ε at the end here, but the statement looks good other than that.Someone2841 said:Let ##f:\mathbb{R} \to \mathbb{R}## be a function such that ## y \mapsto y^2##. To show continuity at every point of ##f##, it is sufficient to demonstrate:
##\forall u \;\; \forall \epsilon > 0 \;\; \exists \delta : \forall y \; \left ( |y-u| < \delta \implies |y^2 - u^2| \right ) ##
Case 1: ##u=0##
Let ##\delta = \sqrt{\epsilon}##. It is clear that ##|y| < \sqrt{\epsilon} \implies |y^2| = \epsilon##.
- ##\delta## can be a function of both ##\epsilon## and ##u## (but not ##y##) for pointwise continuity since they both proceed ##\delta##'s quantifier?
[*]Is ##(|y-u| < \delta) \wedge (\delta < |u|) \implies |y+u| < 3|u|## obvious enough to state without proof?
[*] Obviously, once ##\delta## is chosen, ##|y-u|## could be ##\geq \delta## since both were chosen arbitrarily and without respect to ##\delta##. If this inequality does not hold, neither do the following arguments. Is the parenthetical "(Note: If ##|y-u| \geq \delta## then the continuity condition is met and the argument is complete; assume ##|y-u| < \delta## holds for the remainder of the proof)" sufficient to tackle this problem?
The proof of continuity of y^2 in real analysis involves using the definition of continuity, which states that a function is continuous at a point if the limit of the function at that point exists and is equal to the value of the function at that point. In this case, we are looking at the function y^2, which is continuous at all real numbers.
Proving the continuity of y^2 in real analysis is important because it helps us understand the behavior of this function and its relationship with other functions. It also allows us to use the properties of continuous functions to solve problems and make predictions in real-world applications.
The steps involved in proving the continuity of y^2 in real analysis include defining the function, stating the definition of continuity, showing that the limit of the function exists at a given point, and proving that the limit is equal to the value of the function at that point. This can be done using algebraic manipulation, the epsilon-delta definition, or other techniques.
Yes, the intermediate value theorem can be used to prove the continuity of y^2 in real analysis. This theorem states that if a function is continuous on a closed interval and takes on two different values at the endpoints of the interval, then it must also take on every value in between. In the case of y^2, we can show that it takes on every value between two given points on the real number line, thus proving its continuity.
Yes, there are many real-world applications of the continuity of y^2 in real analysis. For example, it is used in physics to model the motion of objects in free fall, in economics to analyze supply and demand curves, and in engineering to design and optimize structures and systems. It is also used in many other fields such as biology, chemistry, and finance.