Solving the Mystery of Denser Ball in Water: Buoyancy & Density

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When two balls of the same volume but different densities float in water, the denser ball will indeed float deeper. According to Archimedes's principle, the buoyant force acting on each ball must equal its weight. Since the denser ball weighs more, it displaces more water to achieve equilibrium. Therefore, while both balls float, the denser one will have a greater portion submerged. This confirms that the denser ball floats deeper in the water.
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I have a rather simple question which I can't seem to find an answer to

If I have two balls, one denser than the other, but of same volume, and let them float on water, would the denser one float deeper in the water?

The water is the same and the density of the two balls are less than the density of the water. I think the denser one would float but more of it would be submerged. Is this correct?

Thanks
 
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Yes. Just consult Archimedes's principle. In order to float, the buoyant force must equal the weight of the ball. And the buoyant force is always given by the weight of the displaced fluid. So the heavier ball must displace more water in order to float.
 
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