Calculate Instantaneous Voltage of 50 Hz 3-Phase Supply - 100 V

  • Thread starter Thread starter DunceKirchhoff
  • Start date Start date
  • Tags Tags
    Voltage
AI Thread Summary
To calculate the instantaneous voltage of a 50 Hz three-phase supply with a peak voltage of 100 V at 7.5 ms, the sine wave equation V=A*cos(wt+theta) is used, where A is the amplitude, w is the angular frequency, and theta is the phase angle. The angular frequency w is calculated as 2π times the frequency, which for 50 Hz is approximately 314.16 rad/s. Each phase is 120 degrees apart, so the phase angles for the three phases can be represented as 0°, -120°, and -240°. By substituting the time of 7.5 ms into the equation for each phase, the instantaneous voltages can be determined. Understanding the sine wave nature of AC voltage is crucial for accurate calculations.
DunceKirchhoff
Messages
27
Reaction score
0
A 50 Hz ac three phase supply has a peak voltage of 100 V. Calculate the instantaneous voltage of each phase at a time of 7.5 ms.

Looked all over google and can't seem to find an equation for this?

Can anyone point me in the right direction?
 
Physics news on Phys.org
DunceKirchhoff said:
A 50 Hz ac three phase supply has a peak voltage of 100 V. Calculate the instantaneous voltage of each phase at a time of 7.5 ms.
Can you attach a pic of the illustration that accompanied this question?
 
Think about what an AC waveform is. Its a sine wave. the standard form for a sine wave is

V=A*cos(wt+theta) where A=amplitude, w=frequency in radians, & theta=delay.

note with a 3phase system the voltages are evenly out of phase with one another, so they are evenly spread across the unit circle (360 degrees)

Using this information give it another try
 
Back
Top